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Lena [83]
3 years ago
8

Start time 11:00 am elapsed time is 4 hours and 5 minutes what time does it end

Mathematics
2 answers:
pochemuha3 years ago
4 0
11:00 AM + 4 = 3:00 AM,then simply add 5 mins to 3:00,= 3:05 AM.
Vinvika [58]3 years ago
3 0
Remember, when you add the time in, you switch to PM at 12:00 so...

11:00 AM + 4 hrs 5 min =

3:05 PM


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Find the curl of ~V<br> ~V<br> = sin(x) cos(y) tan(z) i + x^2y^2z^2 j + x^4y^4z^4 k
ch4aika [34]

Given

\vec v =  f(x,y,z)\,\vec\imath+g(x,y,z)\,\vec\jmath+h(x,y,z)\,\vec k \\\\ \vec v = \sin(x)\cos(y)\tan(z)\,\vec\imath + x^2y^2z^2\,\vec\jmath+x^4y^4z^4\,\vec k

the curl of \vec v is

\displaystyle \nabla\times\vec v = \left(\frac{\partial h}{\partial y}-\frac{\partial g}{\partial z}\right)\,\vec\imath - \left(\frac{\partial h}{\partial x}-\frac{\partial f}{\partial z}\right)\,\vec\jmath + \left(\frac{\partial g}{\partial x}-\frac{\partial f}{\partial y}\right)\,\vec k

\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ - \left(4x^3y^4z^4-\sin(x)\cos(y)\sec^2(z)\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k

\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ + \left(\sin(x)\cos(y)\sec^2(z)-4x^3y^4z^4\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k

7 0
3 years ago
Bentuk sederhana dari 3√24 2√3(√3-2√18)
Sauron [17]
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3(√(4*6) + 2√3( √3-2√(2*9)) = 
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8 0
3 years ago
In a group of eighteen people, each person shakes hands once with each other person in the group. How many handshakes will occur
miv72 [106K]

The number of handshakes that will occur in a group of eighteen people if each person shakes hands once with each other person in the group is 153 handshakes

In order to determine the number of handshakes that will occur among 18 people, that is, the number of ways we can choose 2 persons from 18 people.

∴ The number of handshakes = ^{18}C_{2}

^{18}C_{2} = \frac{18!}{(18-2)!2!}

^{18}C_{2} = \frac{18!}{16!2!}

^{18}C_{2} = \frac{18\times17\times16!}{16!\times2!}

^{18}C_{2} = \frac{18\times17}{2\times1}

^{18}C_{2} = \frac{306}{2}

^{18}C_{2} = 153

∴ The number of handshakes = 153 handshakes

Hence. 153 handshakes will occur in a group of eighteen people if each person shakes hands once with each other person in the group.

Learn more here: brainly.com/question/1991469

5 0
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Hey yall can come here for the fastest brainliest! But first answer it correctly! cuz it s a easy question plus you get many poi
RideAnS [48]

Answer:

3rd option is correct.....

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Write the English phrase as an algebraic expression. Then simplify the expression. Let x represent the number.
max2010maxim [7]
7(-6x)


its been a long time since ive done something like this lol
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