X= -3/2y+3/17z
y=-2/3x+2/17z
z=-17/3x+17/2y
1. This is a very easy question as you can just plug in 2 x-values and get the y-value, run a line through it, and you are done.
For example,
x = 2t
x = 2(2) = 4
x = 2(3) = 6
Now, you know there are points at (2, 4) and (3, 6).
2. This one is a little tricky, but all it's saying is that it has a specified domain. The parametric equation only works for values -2 ≤ t ≤ 3. So, you can do the exact same thing, except your line will only exist for points through the x-values -2 and 3. Let's plug in numbers:
y = t + 5
y = -2 + 5 = 3
y = 1 + 5 = 6
Now you know that this line runs through (-2, 3) and (1, 6). Remember, your line starts at -2 and ends at 3. It can't go any further than that.
Answer:
see explanation
Step-by-step explanation:
Using the identity
tan x = 
Consider the left side
= 
( multiply numerator and denominator by cos²x to clear fractions
= 
← ( cos²x + sin²x = 1 ]
= cos²x - sin²x
= right side , thus proven
