Answer:
a)Yes Alice can pick 11 has value for her public exponent e
b) The value of d when the public exponent e = 3 is 37
c) The cipher c of the Bob’s message m =2 is 8
d) The cipher c of the Bob’s message m =3 is 18
e) The value of m if c = 3 and the public exponent e = 7 is 16
Explanation:
Find attached the explanation
Eased the mobilization and transportation of troops
Because machine (cpu) can only execute machine code(language).
Answer:
The equivalent if statements is:
ranforce = randi([0, 12]);
if (ranforce == 0)
disp('There is no wind')
else if(ranforce>0 && ranforce <7)
disp('There is a breeze')
else if(ranforce>6 && ranforce <10)
disp('This is a gale')
else if(ranforce>9 && ranforce <12)
disp('It is a storm')
else if(ranforce==12)
disp('Hello, Hurricane!')
end
Explanation:
<em>The solution is straight forward.</em>
<em>All you need to do is to replace the case statements with corresponding if or else if statements as shown in the answer section</em>
To accomplish this without using a loop,
we can use math on a string.
Example:
print("apple" * 8)
Output:
appleappleappleappleappleappleappleapple
In this example,
the multiplication by 8 actually creates 8 copies of the string.
So that's the type of logic we want to apply to our problem.
<span>def powersOfTwo(number):
if number >= 0:
return print("*" * 2**number)
else:
<span>return
Hmm I can't make indentations in this box,
so it's doesn't format correctly.
Hopefully you get the idea though.
We're taking the string containing an asterisk and copying it 2^(number) times.
Beyond that you will need to call the function below.
Test it with some different values.
powersOfTwo(4) should print 2^4 asterisks: ****************</span></span>
