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3 years ago

Hailey paid $13 for 1 3/7 kg of sliced salami. What was the cost per kilogram of salami?

Mathematics

2 answers:

TEA [102]3 years ago

7 0

$9.10 per kilogram of salami

JulijaS [17]3 years ago

6 0

Let's convert 1 3/7 to an improper fraction, and 13 to an improper fraction.
Then multiply=
10/7 x 13/1
But wait! we are dividing so we need to flip "10/7"
7/10x13/1=91/10
Now we reduce that fraction down to 9 1/10
Then we convert that to dollars and cents.
Then we find that they paid $9.10 per kilogram

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Creating an Exponential Model

belka [17]

Answer:

P = $300

r = 0.15

n = 12

$544.61 (to the nearest cent)

$P(1+r)^t$

$524.70 (to the nearest cent)

Step-by-step explanation:

P = principal amount = $300

r = annual interest rate in decimal form = 15% = 15/100 = 0.15

n = number of times interest is compounded per unit t = 12

How much she'll owe in 4 years

P = 300

r = 0.15

n = 12

t = 4

$P(1+\frac{r}{n})^{nt}=300(1+\frac{0.15}{12})^{12 \times 4}$

= $544.61 (to the nearest cent)

Yearly compounding interest rate

$P(1+r)^t$

How much she'll owe in 4 years at yearly compounding interest

$P(1+r)^t=300(1+0.15)^4$

= $524.70 (to the nearest cent)

7 0

3 years ago

Please help me , I don’t understand :(

Yuri [45]

Answer:

A. 1.4 times

Step-by-step explanation:

The factor in this exponential function is 1.4.

Please see the attachment.

7 0

3 years ago

Write the set of points from −6−6 to 33 but excluding −2−2 and 33 as a union of intervals:

Softa [21]

In this question, we have to write the set of points from -6 to 3 but excluding -2 and 3 as a union of intervals .

For union, we use U.

For the points that we have to exclude , we put parenthesis on there side that is ().

Therefore the required interval form is

$[-6,-2)U(-2,3)$

As we see that () are used with -2 and 3 . And that's the required interval form .

5 0

3 years ago

The table shows the average annual cost of tuition at 4-year institutions from 2003 to 2010.

nata0808 [166]

Answer: 1) The best estimate for the average cost of tuition at a 4-year institution starting in 2020 =$ 31524.31

2) The slope of regression line b=937.97 represents the rate of change of average annual cost of tuition at 4-year institutions (y) from 2003 to 2010(x). Here,average annual cost of tuition at 4-year institutions is dependent on school years .

Step-by-step explanation:

1) For the given situation we need to find linear regression equation Y=a+bX for the given situation.

Let x be the number of years starting with 2003 to 2010.

i.e. n=8

and y be the average annual cost of tuition at 4-year institutions from 2003 to 2010.

With reference to table we get

$\sum x=36\\\sum y=150894\\\sum x^2=204\\\sum xy=718418$

By using above values find a and b for Y=a+bX, where b is the slope of regression line.

$a=\frac{(\sum y)(\sum x^2)-(\sum x)(\sum xy)}{n(\sum x^2)-(\sum x)^2}=\frac{150894(204)-(36)718418}{8(204)-(36)^2}=\frac{30782376-25863048}{1632-1296}=\frac{4919328}{336}\\\\=14640.85$

and

$b=\frac{n(\sum xy)-(\sum x)(\sum y)}{n(\sum x^2)-(\sum x)^2}=\frac{8(718418)-(36)150894}{8(204)-(36)^2}=\frac{5747344-5432184}{1632-1296}=\frac{315160}{336}\\\\=937.97$

∴ To find average cost of tuition at a 4-year institution starting in 2020.(as n becomes 18 for year 2020 if starts from 2003 ⇒X=18)

So, Y= 14640.85 + 937.97×18 = 31524.31

∴The best estimate for the average cost of tuition at a 4-year institution starting in 2020 = $31524.31

4 0

3 years ago

Absolute value of 19

Anna007 [38]

The absolute value of 19 is 19

7 0

3 years ago

Read 2 more answers