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gtnhenbr [62]
2 years ago
13

Find all solutions of the equation in the interval [0,2pi) 8sec^2x+4tan^2x-12=0

Mathematics
2 answers:
andrezito [222]2 years ago
6 0
Π/6+2πk
5π/6+2πk
you need to factor and use trig identities

____ [38]2 years ago
3 0
8(1+tan^2x)+4tan^2x-12=0.
8+12tan^2x-12=0
12tan^2x=4
tanx=1/sqrt(3)
x=atan(1/sqrt(3))
x=0.5236
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Answer:

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Step-by-step explanation: You have to combine like terms first:

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Then divide om each side of the equation by -9.7.

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3 years ago
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Answer:

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8 0
2 years ago
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