3 years ago

Find all solutions of the equation in the interval [0,2pi) 8sec^2x+4tan^2x-12=0

Mathematics

2 answers:

andrezito [222]3 years ago

6 0

Π/6+2πk
5π/6+2πk
you need to factor and use trig identities

____ [38]3 years ago

3 0

8(1+tan^2x)+4tan^2x-12=0.
8+12tan^2x-12=0
12tan^2x=4
tanx=1/sqrt(3)
x=atan(1/sqrt(3))
x=0.5236

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