The formula is
A=p (1+rt)
A cost of the car 13080
P amount deposited 12000
R interest rate 0.03
T time?
Solve for t
T=[(A/p)-1]÷r
T=((13,080÷12,000)−1)÷0.03
T=3 years
Answer:
P(x) = x^4 -16x^3 +76x^2 -72x -100
Step-by-step explanation:
The two roots 1-√3 and 1+√3 give rise to the quadratic factor ...
... (x -(1-√3))(x -(1+√3)) = (x-1)^2 -(√3)^2 = x^2 -2x -2
The complex root 7-i has a conjugate that is also a root. These two roots give rise to the quadratic factor ...
... (x -(7 -i))(x -(7 +i)) = (x-7)^2 -(i)^2 = x^2 -14x +50
The product of these two quadratic factors is ...
... P(x) = (x^2 -2x -2)(x^2 -14x +50) = x^4 +x^3(-14 -2) +x^2(50 +28 -2) +x(-100+28) -100
... P(x) = x^4 -16x^3 +76x^2 -72x -100
Answer:
The answer should be 8q-6 i think i tried
Step-by-step explanation:
Answer:
the graph is as illustrated above
The absolute value of x is shifting 3 units up