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3 years ago

Every quotient of two integers( with a nonzero divisor) is an integer

Mathematics

2 answers:

Yuliya22 [10]3 years ago

5 0

Not true. $\dfrac12$ is not an integer, as a counterexample.

lesya [120]3 years ago

3 0

Answer:

Not true. is not an integer, as a counterexample.

1/2 and 1/4

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Anybody knows the answers to the monomial functions ?

Bond [772]

Step-by-step explanation:

A monomial function is an expression with only one term. ... For example, a polynomial function is the sum of many monomial functions; If there's only one term in a polynomial function, then it is a monomial function [2]. Monomial functions can take many forms: A monomial (a number by itself is a “monomial”).

4 0

3 years ago

7. It takes ounces of honey to make one apple pie. Betty baked 4 apple

Rom4ik [11]

Answer:

17.6 ounces to make the pecan pies. I dont know how much honey she used to make the apple pie so if you could pls say I could edit the answer :)

Step-by-step explanation:

4 0

3 years ago

What is the answer please.... need help

mina [271]

Answer:

$f\left(x\right)=x^3-6x^2+3x+10$ is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Step-by-step explanation:

Given the function

$f\left(x\right)=x^3-6x^2+3x+10$

As the highest power of the x-variable is 3 with the leading coefficients of 1.

So, it is clear that the polynomial function of the least degree has the real coefficients and the leading coefficients of 1.

solving to get the zeros

$f\left(x\right)=x^3-6x^2+3x+10$

$0=x^3-6x^2+3x+10$ ∵ $f(x)=0$

$Factor\:x^3-6x^2+3x+10\::\:\left(x+1\right)\left(x-2\right)\left(x-5\right)=0$

$\left(x+1\right)\left(x-2\right)\left(x-5\right)=0$

Using the zero factor principle

if $ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

$x+1=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0$

$x=-1,\:x=2,\:x=5$

Therefore, the zeros of the function are:

$x=-1,\:x=2,\:x=5$

$f\left(x\right)=x^3-6x^2+3x+10$ is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Therefore, the last option is true.

8 0

2 years ago

Armando graphed the relationship between temperature and elevation for several cities. The

Novosadov [1.4K]

Answer:

,lokiu8ytfvgbhnjmkiom nb bnvmkjb nnjn7

Step-by-step explanation:

5 0

3 years ago

Need help with number 43 and 45 and need to show the work

Alex787 [66]

43:
   Negative temperatures are basically the same as normal ones, although they go below zero, so they are still the same distance apart from zero, just on the left side of the number line.

      To find the answer find the difference between 30.5°C and 0 (which is 30.5).

      Next, find the difference between -122.2°C and zero (122.2)

   Finally, add 122.2 + 30.5 to find the total distances from the zero combined for the full distances apart from each other.

   (We add them because -122.2 to the left of zero, and 30.5 is on the right)

      You should get 152.7 as your answer.

45:
   I'm guessing since it is asking for the deepest point (-5315) from sea level (0), the answer is -5,315 feet

   *Remember 5,315 is negative because numbers below sea level are all negative*

   So the answer should be -5,315 feet deep. (I'm not sure how to show your work for that I'm guessing it is 0 - 5,315 at the slightest).

*Hope this all helped :)*

5 0

2 years ago