Given: The systolic arterial blood pressure observed for 20 dogs is normally distributed with a mean of 152 mm of mercury (Hg) and a standard deviation of 18 mm of Hg.
To find: P(100 < 152)
Method: Calculation of Z-Score followed by the probability or area of the bell curve at X = 100.
Solution:
Mean u = 152, std s = 18
Z score = 
The value of P(100<152) is calculated by looking at the value of Z in the Z score for the standard normal distribution given in the image.
P(Z=-2.89) = 0.0019
The P(Z = -2.89) corresponds to the area in the left tail of the bell curve.
Thus the probability of 100 mm Hg blood pressure is 0.0019.
Answer: C) breaking down terminology
Explanation:
Answer:
The answer is below
Explanation:
The possible phenotypes of the mother can be any of the following
AA - A phenotype
AB - AB phenotype (here the mother must have contributed an A gene for it to be possible)
AO - A phenotype (here the mother may have contributed any of the A or O gene.)
BO - B phenotype (here, the mother would only need to contribute O gene for this to be possible)
Answer:
No, it did not rain today in Texas.