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Thepotemich [5.8K]

3 years ago

5

At a sandwich shop, Diana can select from 2 types of bread and 5 types of meat. if she randomly selects 1 type of bread and 1 ty

pe of meat, how many possible choices does she have?

2 answers:

WITCHER [35]3 years ago

5 0

She has 10 choices :)

Elena L [17]3 years ago

5 0

Answer:

10 Choices

Step-by-step explanation:

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3p + 7 = -4(4 - 6p) + 2

zvonat [6]

p=1

Step-by-step explanation:

$3p + 7 = - 4(4 - 6p) + 2 \\ 3p + 7 = - 16 + 24p + 2 \\ 3p - 24p = - 16 + 2 - 7 \\ - 21p = - 21$

$\frac{ - 21p}{ - 21} = \frac{ - 21}{ - 21} \\ p = 1$

3 0

3 years ago

Read 2 more answers

Use the formula A=bhto find the area of the parallelogram.<br> 2.1 m<br> 6.3 m

Feliz [49]

Answer:

A = 13.23 m²

Step-by-step explanation:

A = bh

Where,

A = area of the parallelogram

b = base of the parallelogram

h = height of the parallelogram

From the question, assume

b = 2.1 m

h = 6.3 m

A = bh

= 2.1 m × 6.3 m

= 13.23 m²

A = 13.23 m²

7 0

3 years ago

A structure is an intersecting hip roof with the main hip roof outside dimensions being 73 ft long and the width being 30 ft wid

malfutka [58]

Answer:

35 ft

Step-by-step explanation:

See attached file for detailed solution of the given.

6 0

3 years ago

A person owes a debt of $10

AleksandrR [38]

So the person is out of pocket of $10.00

6 0

3 years ago

The "mammals" data set in the "MASS" library contains the result of a study of sleep in mammal species. 1 2 Load the "mammals" d

dusya [7]

Complete Question:

The complete question is shown on the first uploaded image

Answer:

The probability that the random you randomly select species that are greater than 200 kg is = 7/62

Step-by-step explanation:

Step One: Load the data set in to the R work space

data(mammals,package="MASS")

attach(mammals)

Step 2 : Obtain the list of the species that are greater than 200 and store it on y variable.

y <- subset(mammals,body>200)

Step Three : Obtain the total size

nrow(mammals)

Step Four : Obtain the sum of species greater than 200

sum(body > 200)

total size = 62

size with body > 200 = 7

hence

required probability = 7/62

7 0

3 years ago