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dalvyx [7]
3 years ago
5

Which option correctly describes both domain & the range?

Mathematics
1 answer:
stich3 [128]3 years ago
4 0
Domain refers to all of the x-values that satisfy the line, and the range refers to all of the y-values that satisfy the line.

Since t corresponds to the x-ordinates, then the domain becomes:
0 ≤ t ≤ 6

and the range becomes:
0 ≤ v ≤ 150

In short, the answer is (A)
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What is wrong with the equation? 2 x−3 dx = x−2 −2 2 −3 = − 5 72 −3 f(x) = x−3 is continuous on the interval [−3, 2] so FTC2 can
Wewaii [24]

Answer:

Hello your question is incomplete below  is the complete question

What is wrong with the equation? integral^2 _3 x^-3 dx = x^-2/-2]^2 _3 = -5/72 f(x) = x^-3 is continuous on the interval [-3, 2] so FTC2 cannot be applied. f(x) = x^-3 is not continuous on the interval [-3, 2] so FTC2 cannot be applied. f(x) = x^-3 is not continuous at x = -3, so FTC2 cannot be applied The lower limit is less than 0, so FTC2 cannot be applied. There is nothing wrong with the equation. If f(2) = 14, f' is continuous, and f'(x) dx = 15, what is the value of f(7)? F(7) =

answer : The value of f(7) = 29

Step-by-step explanation:

Attached below is the detailed solution

Hence : F(7) - 14 = 15

F(7) = 15 + 14 = 29

8 0
4 years ago
The figure shows rectangle ABCD composed of three small rectangles of equal size(congruent). If the area of ABCD is 600 what is
Elanso [62]
150 since rectangle has 4 sides, so 600 is divided to 4(sides)=150
4 0
4 years ago
What is the expression x2-4 for a=b=3x=5 and y=4
avanturin [10]

The  expression [ x² - 4 ] doesn't depend on 'a', 'b', or 'y'.
It only depends on 'x'.

You have said that  3x = 5,  so x = 5/3.
Therefore, I may now write '5/3' in place of 'x' in the expression:

                               x²  -  4  =

                             (5/3)² - 4  =

                            (25/9) -  4  =

                            (25/9) - (36/9) =

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8 0
3 years ago
What is the area of the figure in square mm
grandymaker [24]

Answer:

8125 mm

Step-by-step explanation:

Not that sure

5 0
3 years ago
Quadrilateral ABCD undergoes a reflection across the x-axis to form quadrilateral a b c d the coordinates of a r the reflected q
Zina [86]

Solution :

From the figure,

The coordinates of --

A = (-5,-3)

B = (-6,-1)

C = (-3,-1)  

D = (-2,-3)

When it undergoes reflection about x-axis, we have the coordinates of the quadrilateral as

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B' = (-6,+1)

C' = (-3,+1)

D' = (-2,+3)

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C" = (0,1)

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When the quadrilateral moves third and two units up, we get

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D"' = (6,3)

3 0
3 years ago
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