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givi [52]
3 years ago
7

Given that f(x) = 2x + 5 and g(x) = x − 7, solve for f(g(x)) when x = −3.

Mathematics
2 answers:
Gnesinka [82]3 years ago
7 0
F(x)=2x+5, g(x)=x-7

f(g(x))=2(x-7)+5=2x-14+5=2x-9

When x= -3:

2\cdot (-3)-9=-6-9=\boxed{-15}

<em>:)</em>

umka2103 [35]3 years ago
4 0
F(g(x)) is asking us to insert g(x) into each x of f(x).

f(g(x)) = 2(x - 7) + 5
f(g(x)) = 2x - 14 + 5
f(g(x)) = 2x - 9

If x = -3, then we need to find f(g(-3)).

f(g(-3)) = 2(-3) - 9
f(g(-3)) = -6 - 9
f(g(-3)) = -15
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What is the end behavior of the graph of f(x) = – 0.5x^2 – 3x – 4?
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We will see that as x tends to ± ∞, the function tends to -∞.

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<h3><u>What is the end behavior?</u></h3>

We define the end behavior as how the function behaves as x tends to very large, in absolute value, values.

In this case we have a quadratic equation:

f(x) = -0.5*x^2 - 3*x - 4

Here you can see that the leading coefficient is negative, thus, the arms of the graph will go downwards.

This means that in the limits of x ⇒ ∞ and x ⇒ -∞, the function will tend to negative infinity.

Then the end behavior can be written as:

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If you want to learn more about end behavior, you can read:

brainly.com/question/11275875

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