So what you are looking for is the hypotenuse of the triangle DCF.
We know DC is 3cm, so we need CF.
BC and CF and CF create a right triangle.
Using Pythagorean Theorem, CF is about 10.2
Now using Pythagorean Theorem again, 3^2 +10.2^2=113
The sqaureroot of that is 10.6. So 10.6 is your answer
Answer:
Given that,
The number of grams A of a certain radioactive substance present at time, in years
from the present, t is given by the formula

a) To find the initial amount of this substance
At t=0, we get


We know that e^0=1 ( anything to the power zero is 1)
we get,

The initial amount of the substance is 45 grams
b)To find thehalf-life of this substance
To find t when the substance becames half the amount.
A=45/2
Substitute this we get,


Taking natural logarithm on both sides we get,







Half-life of this substance is 154.02
c) To find the amount of substance will be present around in 2500 years
Put t=2500
we get,




The amount of substance will be present around in 2500 years is 0.000585 grams
Answer:
B. 12.5
Step-by-step explanation:
where the box ends on the left side is the 1st quartile.
Answer:
$325
Step-by-step explanation:
To solve this, you first subtract 60 by 18 to get 42
You then divide this by 2 to get 21
So, it'll take 21 minutes