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The angle of elevation of 61° and 72° with the height of the tower being 553.3 m. gives Vic's distance from Dan as approximately 356 meters.
<h3>How can the distance between Vic and Dan be calculated?</h3>Location of Vic relative to the tower = South
Vic's sight angle of elevation to the top of the tower = 61°
Dan's location with respect to the tower = West
Dan's angle of elevation in order to see the top of the tower = 72°
Height of the tower = 553.3m
- Vic's distance from the tower ≈ 306.7 m
Similarly, we have;
- Dan's distance from the tower ≈ 179.8 m
Given that Vic and Dan are at right angles relative to the tower (Vic is on the south of the tower while Dan is at the west), by Pythagorean theorem, the distance between Vic and Dan <em>d </em>is found as follows;
- d = √(306.7² + 179.8²) ≈ 356
Therefore;
- Vic is approximately 356 meters from Dan
Learn more about Pythagorean theorem here:
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Answer:
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Step-by-step explanation:
Please consider the complete question.
A young sumo wrestler decided to go on a special high-protein diet to gain weight rapidly. He gained weight at a rate of 5.5 kilograms per month. After 11 months, he weighed 140 kilograms. Let W(t) denote the sumo wrestler's weight W(measured in kilograms) as a function of time t (measured in months).
Since wrestler gained weight at a rate of 5.5 kilograms per month, so slope of line be 5.5.
Now, we will use point-slope form of equation as:
, where,
m = Slope
= Given point on the line.
Upon substituting coordinates of point (11,140) in above formula, we will get:
Therefore, our required function would be .