3 years ago

What is the center of this circle? What is the radius of this circle?

Mathematics

1 answer:

zimovet [89]3 years ago

4 0

Answer:

The center of a circle is the point from which the circumference is equidistant

Step-by-step explanation:

Radius of a circle is a line drawn from the center of the circle to the circumference.

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Solve the equation 14y+82=6x-20 for x if y is 25

Leni [432]

Answer:

x= 226/3 or 75.33333333333333333333333333333

Step-by-step explanation:

14y+82=6x-20

y=25

Sub y=25 into 14y+82=6x-20

14y+82=6x-20

14(25)+82=6x-20

Calculate as follows:

14(25)+82=6x-20

350+82=6x-20

432=6x-20

Add twenty to both sides:

432+20=6x-20+20

452=6x-0

452=6x

Divide both sides by 6

452=6x

452/6=6x/6

452/6=x

x= 226/3 or 75.33333333333333333333333333333

8 0

2 years ago

Erin invested 15000 some at 5 percent and some at 8 percent annual interest if she recieves an annual return of 930 dollars how

eduard

.08x+.05(15000-x)=930
.08x+750-.05=930
.08x-.05x=930-750
.03x=180
X=180/.03=6,000 at 8%
(15000-6000)=9000 at 5%

8 0

2 years ago

If x-1/x=5 find x^3+1/x^3=?

ipn [44]

$\dfrac{x-1}{x}=5\ \ \ \ /x\neq0\\\\\dfrac{x-1}{x}=\dfrac{5}{1}\ \ \ \ |\text{cross multiply}\\\\5x=x-1\ \ \ \ |-x\\\\5x=1\ \ \ \ |:5\\\\x=0.2\\\\\dfrac{x^3+1}{x^3}=\dfrac{x^3}{x^3}+\dfrac{1}{x^3}=1+\dfrac{1}{x^3}\to1+\dfrac{1}{0.2^3}=1+\dfrac{1}{0.008}\\\\=1+\dfrac{1}{\frac{8}{1,000}}=1+\dfrac{1,000}{8}=1+125=126\\\\\text{Answer:}\ \dfrac{x^3+1}{x^3}=126$