Answer:
0 and 1
Step-by-step explanation:
x² = 3
take the square root of both sides
x = {-√3, √3}
x ≈ {-1.73, 1.75}
Two consecutive integers between 1.73 and 1.75
0 and 1
What a delightful little problem ! (Partly because I could see
right away how to do it, and had the answer in a few minutes,
after a lot of impressive-looking algebra on my scratch-paper.)
Three consecutive integers are . . . x, x+1, and x+2
The smallest two are . . . x and x+1
Their product is . . . . . x(x+1)
5 times the largest one is . . . 5(x+2)
5 less than that is . . . . . . 5(x+2)-5
Now, the conditions of the problem say that <u>x (x + 1) = 5 (x+2) - 5</u>
THAT's the equation we have to solve, to find 'x' .
Eliminate parentheses: x² + x = 5x + 10 - 5
Combine like terms: x² + x = 5x + 5
Subtract 5x from each side: x² - 4x = 5
Subtract 5 from each side: <u>x² - 4x - 5 = 0</u>
You could solve that by factoring it, or use the quadratic equation.
Factored, it says that (x + 1) (x - 5) = 0
From which <em>x = -1</em>
and <em>x = +5</em>
We only want the positive results, so our three consecutive integers are
5, 6, and 7 .
To answer the question, the smallest one is <em><u>5 </u></em>.
<u>Check</u>:
5 x 6 ? = ? (7 x 5) - 5
30 ? = ? (35) - 5
30 = 30
yay !
Answer:
13
Step-by-step explanation:
If x is 7, then 7 * 2 = 13, and 14 - 1 = 13.
Hope that this helps!
3 and -3 are said to be the square roots of 9. A square root is written with a radical symbol √ and the number or expression inside the radical symbol, below denoted a, is called the radicand. ... Negative numbers don't have real square roots since a square is either positive or 0.
The answer would Be C. Or B
Your welcome!!!!!!!
