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icang [17]
4 years ago
10

ANSWER ASAP What is the value of the expression when a = 4, b = 3 ,and c = 10? 3a4b−c

Mathematics
2 answers:
Lelu [443]4 years ago
8 0

Answer:    134

Step-by-step explanation:

(3 x a x 4 x b)-c     = (3 x 4 x 4 x 3)-10

                             = (12 x 12) - 10

                             = 144 - 10

                             = 134

Anarel [89]4 years ago
5 0
The answer would be 134
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3 years ago
The weight of turkeys is normally distributed with a mean of 22 pounds and a standard deviation of 5 pounds. a. Find the probabi
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a. 0.443

b. 0.023

Step-by-step explanation:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The weight of turkeys is normally distributed with a mean of 22 pounds and a standard deviation of 5 pounds.

This means that \mu = 22, \sigma = 5

a. Find the probability that a randomly selected turkey weighs between 20 and 26 pounds.

This is the pvalue of Z when X = 26 subtracted by the pvalue of Z when X = 20. So

X = 26

Z = \frac{X - \mu}{\sigma}

Z = \frac{26 - 22}{5}

Z = 0.8

Z = 0.8 has a pvalue of 0.788

X = 20

Z = \frac{X - \mu}{\sigma}

Z = \frac{20 - 22}{5}

Z = -0.4

Z = -0.4 has a pvalue of 0.345

0.788 - 0.345 = 0.443

The answer is 0.443

b. Find the probability that a randomly selected turkey weighs below 12 pounds.

This is the pvalue of Z when X = 12. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{12 - 22}{5}

Z = -2

Z = -2 has a pvalue of 0.023

The answer is 0.023.

8 0
3 years ago
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