Jada’s robot walked out 1 foot and then half of that length again

99% of all confidence intervals with a 99% confidence level should contain the population parameter of interest. true or false

tester [92]

The statement that 99% of all confidence intervals with a 99% confidence level should contain the population parameter of interest is false.

A confidence interval (CI) is essentially a range of estimates for an unknown parameter in frequentist statistics. The most frequent confidence level is 95%, but other levels, such 90% or 99%, are infrequently used for generating confidence intervals.

The confidence level is a measurement of the proportion of long-term associated CIs that include the parameter's true value. This is closely related to the moment-based estimate approach.

In a straightforward illustration, when the population mean is the quantity that needs to be estimated, the sample mean is a straightforward estimate. The population variance can also be calculated using the sample variance. Using the sample mean and the true mean's probability.

Hence we can generally infer that the given statement is false.

To learn more about confidence intervals visit:

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6 0

1 year ago

Babies born after 40 weeks gestation have a mean length of 52.2 centimeters (about 20.6 inches). Babies born one month early hav

Sveta_85 [38]

Answer:

a) $Z = -2.88$

b) $Z = -0.96$

c) 40 weeks gestation babies

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

a. Find the standardized score (z-score), relative to all U.S. births, for a baby with a birth length of 45 cm.

Here, we use $\mu = 52.2, \sigma = 2.5$ . So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{45 - 52.2}{2.5}$

$Z = -2.88$

b. Find the standardized score of a birth length of 45 cm. for babies born one month early, using 47.4 as the mean.

Here, we use $\mu = 47.4, \sigma = 2.5$ . So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{45 - 47.4}{2.5}$

$Z = -0.96$

c. For which group is a birth length of 45 cm more common?

For each group, the probability is 1 subtracted by the pvalue of Z.

Z = -2.88 has a lower pvalue than Z = -0.96, so for Z = -2.88 the probability 1 - pvalue of Z will be greater. This means that for 40 weeks gestation babies a birth length of 45 cm is more common.

3 0

3 years ago

Question 6 (1 point)

vlada-n [284]

Answer:

Zero

Step-by-step explanation:

3x - 7 = 3x - 9 + 2

3x - 7 = 3x - 7

Add 7 on both sides

3x = 3x

Subtract 3x you get 0.

Hope this helps.

4 0

3 years ago

Two numbers differ by 30. If 15 is added to the smaller, the result exceeds half the larger number by 7 1/2. What are the number

katen-ka-za [31]

6*5=30
10*3=30
15+15=30

3 0

3 years ago

Write the point-slope form of the equation of the line that passes through the origin and has a slope of 2. Include your work in

Shkiper50 [21]

Y=2x+0. The two would be next to the x, because that represents the slope. And it would plus zero, because zero is the initial value, since it's passing through the origin.

3 0

3 years ago