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umka2103 [35]
4 years ago
12

9e−7=7e−11 what does e=

Mathematics
2 answers:
evablogger [386]4 years ago
7 0
E would equal 2 I hope this helps
jarptica [38.1K]4 years ago
4 0
E=MC^2 Einseins theory of relativity?

I like to make science jokes
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Mr. Steiner purchased a car for about $14,000. Assuming his loan was
djverab [1.8K]

Answer:

$415.18

Explanation:

The calculation of the present value of a cash flow or other income stream that produces $1 in income over so many periods of time.

DATA

Amount borrowed = $12,500

Annual interest rate = 12.00%

Monthly interest rate = 1.00%

Period = 36 months

Let monthly payment be x

12,500 = x/1.01 + x/1.01^2 + x/1.01^3  … + x/1.01^35 + x/1.01^36

12,500 = x * (1 - (1/1.01)^36) / 0.01

12,500 = x * 30.107505

x = 12,500/30.107505  

x = 415.18

The monthly payment is $415.18

5 0
3 years ago
jason voorhes was buying hocky masks. 1 hockey mask cost 10 dollars how much does 10 masks it cost in all?
Furkat [3]
The total cost would be $100
7 0
3 years ago
Read 2 more answers
The diagonal of a square are _
Elan Coil [88]

Answer:

D. perpendicular

Step-by-step explanation:

The sides of squares are congruent. The diagonal bisects it's angles .The diagonal are perpendicular bisector of each other.

4 0
3 years ago
Factor completely.<br> 2x^4 + 4x^3 - 30x^2 =
den301095 [7]

Answer:

2x^2(x-3)(x+5)

Step-by-step explanation:

The first thing that you can do is to factor out an x^2 from the expression.

x^2(2x^2+4x-30)

The next step is to factor out a 2.

2x^2(x^2+2x-15)

Finally, you can factor the quadratic inside.

2x^2(x-3)(x+5)

And now you're finished! Hope this helps!

6 0
4 years ago
Read 2 more answers
The harmonic motion of a particle is given by f(t) = 2 cos(3t) + 3 sin(2t), 0 ≤ t ≤ 8. (a) When is the position function decreas
iren [92.7K]

For the last part, you have to find where f'(t) attains its maximum over 0\le t\le8. We have

f'(t)=-6\sin3t+6\cos2t

so that

f''(t)=-18\cos3t-12\sin2t

with critical points at t such that

-18\cos3t-12\sin2t=0

3\cos3t+2\sin2t=0

3(\cos^3t-3\cos t\sin^2t)+4\sin t\cos t=0

\cos t(3\cos^2t-9\sin^2t+4\sin t)=0

\cos t(12\sin^2t-4\sin t-3)=0

So either

\cos t=0\implies t=\dfrac{(2n+1)\pi}2

or

12\sin^2t-4\sin t-3=0\implies\sin t=\dfrac{1\pm\sqrt{10}}6\implies t=\sin^{-1}\dfrac{1\pm\sqrt{10}}6+2n\pi

where n is any integer. We get 8 solutions over the given interval with n=0,1,2 from the first set of solutions, n=0,1 from the set of solutions where \sin t=\dfrac{1+\sqrt{10}}6, and n=1 from the set of solutions where \sin t=\dfrac{1-\sqrt{10}}6. They are approximately

\dfrac\pi2\approx2

\dfrac{3\pi}2\approx5

\dfrac{5\pi}2\approx8

\sin^{-1}\dfrac{1+\sqrt{10}}6\approx1

2\pi+\sin^{-1}\dfrac{1+\sqrt{10}}6\approx7

2\pi+\sin^{-1}\dfrac{1-\sqrt{10}}6\approx6

4 0
3 years ago
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