This gives you three simultaneous equations:
6 = a + c
7 = 4a + c
1 = c
<u>c = 1
</u><u /><u />
If c =1,
6 = a + 1
<u>a = 5
</u><u /><u />
This doesn't work in the second equation, so the quadratic that goes through these points is not in the form y = ax^2 + bx + c
Was there supposed to be a b in the equation?
Answer:
JMK = 54
JKH = 126
HLK = 90
HJL = 27
LHK = 63
JLK = 27
Step-by-step explanation:
Just use 180 for total angles in each triangle. Vertical angles mean the opposite to 126 is 126 and the other two that make up the inner vertices are (360- 126*2)/2 = 54
So, 126, `16, 54 , 54 are the inner angles in the circle. Just go from there.
Hi there! The answer is B. it would be less steep.
The change of the function (in this case) influences the slope of the line. Since we've modified the slope from 5 to 3/4, the line will be less steep.
