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umka2103 [35]
3 years ago
12

9e−7=7e−11 what does e=

Mathematics
2 answers:
evablogger [386]3 years ago
7 0
E would equal 2 I hope this helps
jarptica [38.1K]3 years ago
4 0
E=MC^2 Einseins theory of relativity?

I like to make science jokes
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Describe does Glide Reflection from the preimage triangle and black to the image triangle in red
AveGali [126]

Answer:

d

Step-by-step explanation:

Lets look at V which is at (2,-4).

We will also look at it's image V' which is at (-2,-1).

Let's go through the choices:

a. translation left 4 units and down 1 unit reflection x axis

Translating V left 4 and down 1 would give us (2-4,-4-1)

(-2,-5)

Reflecting that across the x-axis would give us

(-2,5).

So this is not (-2,-1) so let's move on...

b. translation left 2 units and up 2 units reflection line x=1

Translating V left 2 and up 2 gives us

(2-2,-4+2)

(0,-2)

Now reflecting this over x=1 gives us

(2,-2). ( Imagine this x=1 which is verical going right smack between points (0,-2) and (2,-2).)

We still did not reach our goal image.

c. translation left 2 units up and up 3 units reflection y axis

Starting at V(2,-4) and moving left 2 & up 3 gives (2-2,-4+3)=(0,-1).

Now reflecting this over the vertical axis, the y-axis, gives us (0,-1).

So we did not reach our (-2,-1) point yet.

d. translation left 2 units and 3 units reflection line x=-1.

​Starting at (2,-4) then moving left 2 and up 3 gives us (2-2,-4+3)=(0,-1).

Now we are reflecting over x=-1 which means we want to choose a point on the side making x=-1 the middle. Thuis point on the other side of (0,-1) of x=-1 would be (-2,-1) which is the goal.

8 0
3 years ago
find the point-slope equation of the line perpendicular to the line y=2x+5 passing through the point (1,4). (please include solu
pishuonlain [190]
First off, let's keep in mind that perpendicular lines have negative reciprocal slopes, hmmm so what's the slope of y = 2x + 5?

well, notice, that equation is in slope-intercept form, thus   \bf y=\stackrel{slope}{2}x+5.

\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}}
{2\implies \stackrel{slope}{\cfrac{2}{1}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{1}{2}}\qquad \stackrel{negative~reciprocal}{-\cfrac{1}{2}}}

so, we're really looking for the equation of a line whose slope is -1/2 and runs through 1,4.

\bf (\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad \qquad \qquad 
slope =  m\implies -\cfrac{1}{2}
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-4=-\cfrac{1}{2}(x-1)
7 0
2 years ago
A zoo orders food in bulk for it's animals. they order enough fresh fruit to last 10 days, enough fresh vegetables for 7 days, a
hammer [34]

Answer:

The answer to this question is C.) 70 Days

7 0
2 years ago
John finished 3/4 pages of his homework in 2/3 of an hour. How many hours will it take him to finish 3 pages of homework? (in a
kykrilka [37]

Answer:

hehejejejejejejejejeheheheheheStep-by-step explanation:

7 0
2 years ago
Consider triangle ABC where AB=X+5, BC=X-2, area is 30cm squared. Find X by solving X^2+3X-70=0, and find the perimeter.
klasskru [66]

Answer:

What the hell AC is not given so you can't find the Perimeter

Step-by-step explanation:

  • x^2+3x-70=0
  • (x-7)(x+10)=0
  • x-7=0

       x+10=0

  • x=7

       x=-10

AB=x+5

  • AB=12

        AB=-5

BC=x-2

  • BC=5

        BC=-12

Area of ABC = 30cm2

<u>Perimeter of ABC = AB+BC+</u><u>AC</u>

<u />

8 0
2 years ago
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