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3 years ago

Based on the diagram, which expresses all possible lengths of segment AB?

Mathematics

1 answer:

ZanzabumX [31]3 years ago

4 0

Answer:

You need to link a diagram

Step-by-step explanation:

Try taking a screenshot or picture and attach it to the question so we can actually see the diagram

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PLEASE HELP ME!!! ANSWER BOTH QUESTIONS & I WILL MARK BRAINLIEST!!!

Nataly [62]

1)b
2)a
Let me know if u want me to show my work

5 0

3 years ago

The value of a company's stock decreases by $15,000. If each share decreased in value from $8 1/16 to $8.00 how many shares are

lina2011 [118]

There are 1875 shares in the company i believe

4 0

3 years ago

Your class raised money by selling hot dogs and hamburgers. Hot dogs were sold for $.50 (fifty cents), and hamburgers were sold

LenKa [72]

Answer:

Number of hot dogs sold = 56

Number of hamburgers sold = 52

Step-by-step explanation:

Let

Number of hot dogs sold = x

Number of hamburgers sold = y

We can make equation from given equations:

$0.50x+1y=80$ (Hot dogs were sold for $.50 (fifty cents), and hamburgers were sold for $1 (one dollar). The total money raised by your class was $80. )

$x+y=108$ (Together you sold 108 hot dogs and hamburgers.)

Now we cam solve these system of equations to find value of x and y

$0.50x+y=80--eq(1)\\x+y=108--eq(2)$

Subtract both equations to get value of x:

$0.50x+y=80\\x\:\:\:\:\:\:\:\: + y=108\\-\:\:\:\:\:\:\:\: -\:\:\:\:\:\: -\\---------\\-0.5x=-28\\x=\frac{-28}{-0.5}\\x=56$

We get value of x = 56

Now putting value of x in equation 2 to find value of y

$x+y=108\\56+y=108\\y=108-56\\y=52$

So, we get y = 52

Therefore,

Number of hot dogs sold = x = 56

Number of hamburgers sold = y = 52

6 0

3 years ago

What a person puts into their relationship is proportional to what they feel they receive; this balance is called

Gnesinka [82]

Answer:

p;smfdr

Step-by-step explanation:

8 0

2 years ago

Write down a differential equation of the form dy/dt = ay + b whose solutions have the required behavior as t → ∞. all other sol

nordsb [41]

The ODE has an equilibrium point at

$\dfrac{\mathrm dy}{\mathrm dt}=ay+b=0\implies y=-\dfrac ba$

We want $y=2$ to be an unstable equilibrium solution - in other words, we want all solutions with initial condition $y(t_0)=c$ for $c$ near 2 to diverge from $y=2$ - so $-dfrac ba=2$ .

Divergence from $y=2$ would require that for $y>2$ , any solution is increasing, and for $y$ , and solution is decreasing. In order for that to happen, we need