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Darya [45]
3 years ago
10

Scott needs to memorize words on a vocabulary list for German class. He has six words to memorize and he is 2/3 done. How many w

ords has Scott memorize so far?
Mathematics
1 answer:
erica [24]3 years ago
5 0

Answer:

4

Step-by-step explanation:

Scott has 6 words to memorize and he as done 2/3 of it, therefore the total number of words will be 2/3 of 6 = 4.

2/3 x 6 = 4

You might be interested in
Please give me the right answer?
baherus [9]

(5 3/10) (m) + (5 3/10) (m) + (5 3/10) (m) + (5 3/10) (m)

P = 53/10 + 5 3/10 + 5 3/10 + 5 3/10

P = 53/10 + 53/10 + 5 3/10 + 5 3/10

P = 53/5 + 5 3/10 + 5 3/10

P = 53/5 + 53/10 + 5 3/10

P = 159/10 + 5 3/10

P = 159/10 + 53/10

P = 106/5

P = 21 1/5 meters

Answer: 21 1/5 meters (Decimal: 21.2m)

Hope that helps!!!! Have a great day!!!! : )

7 0
3 years ago
Please Help!! Which graph shows the solution to this system of inequalities?
scoundrel [369]

Answer:

A. The first graph

Step-by-step explanation:

When you graph these two equations on a graphing calc, you should be able to see one dotted line and one solid, as well as the solutions being mostly in the 1st quadrant.

7 0
4 years ago
Billy anderson is choosing between two fitness centers. Center A charges $495 per year for unlimited use of all facilities. Cent
GREYUIT [131]

Let's compare the cost of both the centers.

<u>Cost of Center A:</u>

One time charge of $495 in one year.

<u>Cost of Center B:</u>

  • Flat $25 dollar sign up fee
  • $15 per month, so 15*12=180 dollars a year
  • $5 per aerobic class, so 5*52=260 dollars a year (given that Billy goes to class once a week) (<em>Note: There are 52 weeks in a year</em>)

Total cost = 25+180+260=465 dollars

Hence, Center B would cost 495-465=30 dollars cheaper.


ANSWER: Least expensive club for Billy to use for a year is Center B

5 0
3 years ago
Read 2 more answers
1. Find the Least Common Multiple of these two monomials:<br> See picture
gtnhenbr [62]

Answer:

<em>The last choice is correct</em>

<em />LCM=120a^4b^7c^5<em />

Step-by-step explanation:

<u>Least Common Multiple (LCM)</u>

To find the LCM we can follow this procedure:

List the prime factors of each monomial.

Multiply each factor the greatest number of times it occurs in either factor.

We have two monomials:

12a^4b^2c^5

40a^3b^7c^1

The prime factors of the first monomial are:

2^2,3,a^4,b^2,c^5

The prime factors of the second monomial are:

2^3,5,a^3b^7c^1

LCM = Multiply 2^3*3*5*a^4*b^7*c^5

These are all the factors the greatest number of times they occur.

Operating:

LCM=8*15*a^4*b^7*c^5

\boxed{LCM=120a^4b^7c^5}

The last choice is correct

3 0
4 years ago
The box plot show the weights in ounces of 15 different bags of almonds. About how many bags contained less than 27 ounces:
andre [41]

Answer:

See explanation

Step-by-step explanation:

The question is incomplete, as the box plot is not given. A general approach to the question, is as follows:

First, identify the 27 mark on the box plot.

Next, count the number of data less than 27.

Take, for instance, there are 6  dots or marks before 27;

This means that 6 bags contain  less than 27 ounces

4 0
3 years ago
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