Let the cost of a lamp = x
6 lamps would cost 6x
He bought 3 lamps at 3x plus Thad 950 left.
3 lamps plus the 950
Would be the same amount as 6 lamps:
Set up an equation and solve for x:
3x + 950 = 6x
Subtract 3x from both sides:
950 = 3x
Divide both sides by 3:
X = 316.67
Each lamp was $316.67
Multiply the price of a lamp by 6:
316.67 x 6 = 1900
He had $1900
2/9; the coefficient is just what’s attached to the variable
We can solve by using the substitution method
y=-5/3x+3
y=1/3x-3
They are equal to each other because they are both equal to y
-5/3x+3=1/3x-3
Subtract both sides by 1/3 and subtract 3 from both sides
-5/3x-1/3x=-3-3
-2x=-6
Divide both sides by -2
x=3
Plug in x into one of the equation to solve for y
y=1/3(3)-3
y=1-3
y=-2
(3,-2)
