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3 years ago

Andrea earns $32.25 a day. After 9 days, about how much will she have earned?

Mathematics

2 answers:

Zanzabum3 years ago

8 0

Answer:

290.25 dollars earned

Step-by-step explanation:

32.25 times 9

11111nata11111 [884]3 years ago

5 0

Answer:

Step-by-step explanation:

since she earns $32.25 a day, we have to multiply this by 9 days.

9 x 32.25 = $290.25

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Which absolute value expression represents the distance between the points shown on the number line

RUDIKE [14]

Answer: c

Step-by-step explanation:

The distance between the 2 numbers is 5 and -4 + -1 is -5, but because your looking for the absolute value which always makes a number positive the answer is 5.

6 0

3 years ago

Read 2 more answers

If A(4 -6) B(3 -2) and C (5 2) are the vertices of a triangle ABC fine the length of the median AD from A to BC. Also verify tha

Gnoma [55]

Answer:

a) The median AD from A to BC has a length of 6.

b) Areas of triangles ABD and ACD are the same.

Step-by-step explanation:

a) A median is a line that begin in a vertix and end at a midpoint of a side opposite to vertix. As first step the location of the point is determined:

$D (x,y) = \left(\frac{x_{B}+x_{C}}{2},\frac{y_{B}+y_{C}}{2} \right)$

$D(x,y) = \left(\frac{3 + 5}{2},\frac{-2 + 2}{2} \right)$

$D(x,y) = (4,0)$

The length of the median AD is calculated by the Pythagorean Theorem:

$AD = \sqrt{(x_{D}-x_{A})^{2}+ (y_{D}-y_{A})^{2}}$

$AD = \sqrt{(4-4)^{2}+[0-(-6)]^{2}}$

$AD = 6$

The median AD from A to BC has a length of 6.

b) In order to compare both areas, all lengths must be found with the help of Pythagorean Theorem:

$AB = \sqrt{(x_{B}-x_{A})^{2}+ (y_{B}-y_{A})^{2}}$

$AB = \sqrt{(3-4)^{2}+[-2-(-6)]^{2}}$

$AB \approx 4.123$

$AC = \sqrt{(x_{C}-x_{A})^{2}+ (y_{C}-y_{A})^{2}}$

$AC = \sqrt{(5-4)^{2}+[2-(-6)]^{2}}$

$AC \approx 4.123$

$BC = \sqrt{(x_{C}-x_{B})^{2}+ (y_{C}-y_{B})^{2}}$

$BC = \sqrt{(5-3)^{2}+[2-(-2)]^{2}}$

$BC \approx 4.472$

$BD = CD = \frac{1}{2}\cdot BC$ (by the definition of median)

$BD = CD = \frac{1}{2} \cdot (4.472)$

$BD = CD = 2.236$

$AD = 6$

The area of any triangle can be calculated in terms of their side length. Now, equations to determine the areas of triangles ABD and ACD are described below:

$A_{ABD} = \sqrt{s_{ABD}\cdot (s_{ABD}-AB)\cdot (s_{ABD}-BD)\cdot (s_{ABD}-AD)}$ , where $s_{ABD} = \frac{AB+BD+AD}{2}$

$A_{ACD} = \sqrt{s_{ACD}\cdot (s_{ACD}-AC)\cdot (s_{ACD}-CD)\cdot (s_{ACD}-AD)}$ , where $s_{ACD} = \frac{AC+CD+AD}{2}$

Finally,

$s_{ABD} = \frac{4.123+2.236+6}{2}$

$s_{ABD} = 6.180$

$A_{ABD} = \sqrt{(6.180)\cdot (6.180-4.123)\cdot (6.180-2.236)\cdot (6.180-6)}$

$A_{ABD} \approx 3.004$

$s_{ACD} = \frac{4.123+2.236+6}{2}$

$s_{ACD} = 6.180$

$A_{ACD} = \sqrt{(6.180)\cdot (6.180-4.123)\cdot (6.180-2.236)\cdot (6.180-6)}$

$A_{ACD} \approx 3.004$

Therefore, areas of triangles ABD and ACD are the same.

4 0

4 years ago

Which if the following is the equation of a line that passes through the points (2,5) and (4,3)

Taya2010 [7]

Hi there!

First, let's find the slope of the two points using the slope formula (y2 - y1 / x2 - x1).

S = 4 - 2 / 3 - 5
S = 2 / -2
S = -1

Next, we'll plug in the slope and a point into point-slope form (y - y1 = s(x - x1)) in order to find an equation. I will show the work using both points, which will result in two different equations.

(2,5)
y - 5 = -1(x - 2)
y - 5 = -x + 2
y = -x + 7

(4,3)
y - 3 = -1(x - 4)
y - 3 = -x + 4
y = -x + 7

The two equations came out the same! Which is completely okay, and happens sometimes.

Hope this helps!! :)
If there's anything else that you're needing help with, don't be afraid to reach out!

3 0

4 years ago

When p2 – 4p is subtracted from p2 + p – 6, the result is 5p-6 To get p – 9, subtract

jeka57 [31]

$(p^{2} + p - 6) - (x) = p - 9

$ is what is asked.

So all you need to do is a value that will result to p - 9.

x = $(p^{2} + p - 6) - p + 9$ To isolate x we just transpose the values from the other side of the equation and do the opposite operation.

Combine like terms and just copy the terms that do not have similar expressions:

p will cancel out because p - p = 0
-6 and + 9 will come together because they are like terms: -6 + 9 = 3
$p^{2}$ does not have a pair so it will remain as is. you will be left with:

$p^{2} + 3$

Let us check:

$p^{2} + p - 6$
- $p^{2} + 0 + 3$
----------------------------
$0 + p - 9$ or $p -9$