Is this correct? |-4+5i| √-4²+5² √-16+25 √-9 =3

The volume of a rectangular prism is (x^4+4x^3+3x^2+8x+4), and the area of its base is (x^3+ 3x^2+8). If the volume of a rectang

vovikov84 [41]

1) Volume = area * height => height = volume / area

2)

x^4 + 4x^3 + 3x^2 + 8x + 4
height = --------------------------------------
x^3 + 3x^2 + 8

That division is not exact

The result of this division is x + 1 plus a residue of - 8x^2 + 8x - 4.

It was expected an exact division, so likely some of the terms is not properly written. Now you know the procedure and can perform it with the right terms.

7 0

3 years ago

There are 7 more quarters than nickels. If there is a total of $ 2.65 in coins, how many quarters are there?

Solnce55 [7]

o=nickel

O=quarter

O O O O O O O O O O + o o o =2.65

(2.50+.15=2.65)

there are 10 quarters total, and 3 nickels

5 0

2 years ago

5692 in standard form

Mamont248 [21]

Answer:

5.692 × 103.

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Determine whether a probability distribution is given. If a probability distribution is given, find its mean and standard deviat

drek231 [11]

Answer:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

Step-by-step explanation:

For this case we have the following probability distribution given:

X 0 1 2 3 4 5

P(X) 0.031 0.156 0.313 0.313 0.156 0.031

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).

We can verify that:

$\sum_{i=1}^n P(X_i) = 1$

And $P(X_i) \geq 0, \forall x_i$

So then we have a probability distribution

We can calculate the expected value with the following formula:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

6 0

3 years ago

Triangle S and Triangle L are scaled copies of one

tatiyna

Answer:

2

Step-by-step explanation:

The bottom of S is 2 units and the bottom of L is 4 Units.

4:2 is the ratio, and that is equal to 2

3 0

2 years ago