Answer:
fog = 2√(x-1) + 1
Domain = [1, 
)
Step-by-step explanation:
Given the functions f(x)=2x+1 and g(x)=sqrt(x-1), we are to find the composite function fog
fog = f(g(x))
f(g(x)) = f(√(x-1))
f(√(x+1)) means that we are to replace variable x in f(x) with the function √(x-1)
f(√(x-1)) = 2(√(x-1))+1
f(√(x+1)) = 2√(x-1) + 1
fog = 2√(x-1) + 1
<em>For the function to exist on any real valued function, then the function inside square root i.e x-1 must be greater than or equal to zero (x-1≥0)</em>
If x-1≥0
x≥0+1
x≥1
This means the range of variable x must be values of x greater than or equal to 1.
Domain = [1, )
Answer:
D
Step-by-step explanation:
This is an example of the Pythagorean theorem.
In triangle BEH, the sum of the squares of the sides of the two smaller sides, BE and BH is equal to the longest side squared, EH.
Answer:
y = 11.5
Step-by-step explanation:
Given 2 secants from an external point to the circle.
Then the product of the external part and the whole of one secant is equal to the product of the external part and the whole of the other secant, that is
6(6 + y) = 5(5 + 16)
36 + 6y = 5 × 21 = 105 ( subtract 36 from both sides )
6y = 69 ( divide both parts by 6 )
y = 11.5
Aight so first you need to isolate the y. Simply add 8 to both sides and now you have 1/4y = 33. Now divide both sides by 1/4 (which is the same by multiplying by 4) and you get 132
Answer:
A graph with a set amount of numbers.
Step-by-step explanation:
Infinite means never ending and that's what most graphs are. But, a finite graph is a graph that doesn't have arrows at the end of the lines. (simplified answer) A better way of saying it is a graph with a fixed starting position and a fixed ending position. You can use this type of graph if you don't want to go over or under a certain value.
Hope this helps!
