Question

Find the equation of a line passing through (-3, 3) and parallel to 4x + 3y =3

Answer 1

Answer:

$4x + 3y = - 3$

Step-by-step explanation:

The line is parallel to 4x+3y=3.

We rewrite this line in slope intercept form to deduce our slope.

$y = - \frac{4}{3} x + 3$

The slope is

$m = - \frac{4}{3}$

The line passes through (-3,3) so we use the point-slope formula:

$y-y_1=m(x-x_1)$

$y - 3 = - \frac{4}{3} (x - - 3)$

We simplify to get:

$y= - \frac{4}{3}x - 4 + 3$

$y= - \frac{4}{3}x - 1$

We rewrite in standard form to get:

$3y = - 4x - 3$

$3y + 4x = - 3$