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katrin [286]
3 years ago
15

Bailey, Jeremiah, and Maggie are buying school supplies. Bailey buys 2 pens and 6 pencils and spends a total of $7.00. Jeremiah

buys 3 pens and 5 pencils and spends a total of $7.50. How much will Maggie spend to purchase 4 pens? *
3 points
Mathematics
1 answer:
CaHeK987 [17]3 years ago
4 0
<h2>Explanation:</h2>

Here we have to solve a system of linear equations in three variables. Let:

x: Cost of pens

y: Cost of pencils

We know that:

  • Bailey buys 2 pens and 6 pencils and spends a total of $7.00. So:

2x+6y=7 \ ... \ eq1

  • Jeremiah buys 3 pens and 5 pencils and spends a total of $7.50. So:

3x+5y=7.5 \ ... \ eq2

Multiplying eq1 by 3 and eq 2 by -2:

\bullet \ 3(2x+6y)=3(7) \\ \\ 6x+18y=21 \\ \\ \\ \bullet \ -2(3x+5y)=-2(7.5) \\ \\ -6x-10=-15

Then adding these two resultant equations:

6x+18y=21 \\ \\ -6x-10y=-15 \\ \_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_ \\ \\ 8y=6 \\ \\ y=0.75 \\ \\ \\ So \ from \ eq \ 1: \\ \\ 2x+6(0.75)=7 \\ \\ 2x=7-4.5 \\ \\ 2x=2.5 \\ \\ x=1.25

How much will Maggie spend to purchase 4 pens?

Each pen costs $1.24, so 4 pens will cost:

\text{Cost of 4 pens}=4(1.25)=\boxed{\$5}

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MA_775_DIABLO [31]

Label the vertices A (- 3, - 2), B (- 7, - 3 ), D (- 4, - 5 )

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CA = a - c = < - 3, - 2 > - < - 7, - 6 > = < 4, 4 >

CA' = 3 < 4, 4 > = < 12, 12 >

A' = (- 7 + 12, - 6 + 12 ) = ( 5, 6 )

CB = b - c = < - 7, - 3 > - < - 7, - 6 > = < 0, 3 >

CB' = 3 < 0, 3 > = < 0, 9 >

B' = (- 7 + 0, - 6 + 9 ) = (- 7, 3 )

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Summarising

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(- 7, - 3 ) ⇒ (- 7, 3 )

(- 4, - 5 ) ⇒ (2, - 3 )





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