Order the following from smallest to largest. .84, 2.83, .065

A credit card company charges a customer 1.1% per month on the unpaid balance of charges on a credit card. What is the finance c

Mars2501 [29]

1.1% converts to 0.011 after moving the decimal point 2 spots to the left

Multiply this with 845.12
845.12*0.011 = 9.29632

Round 9.29632 to the nearest penny to get 9.30

Answer: B) $9.30

4 0

3 years ago

What’s the distance between (8,-5 ) and (6,4)

Ierofanga [76]

Answer:

Step-by-step explanation:

d^2=(x2-x1)^2+(y2-y1)^2

d^2=(6-8)^2+(4+5)^2

d^2=4+81

d^2=85

d=(85)^(1/2)

d=9.22 (rounded to nearest hundredth)

6 0

3 years ago

Read 2 more answers

A sample from a population with μ = 40 and σ = 8 has a mean of M = 36. If the sample mean corresponds to a z = –1.00, then how m

juin [17]

Answer:

There are 4 scores in the sample.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

$\mu = 40, \sigma = 8, X = 36, Z = -1, s = \frac{8}{\sqrt{n}}$

We want to find n. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$-1 = \frac{36 - 40}{\frac{8}{\sqrt{n}}}$

$-4\sqrt{n} = -8$

$4\sqrt{n} = 8$

Simplifying by 4

$\sqrt{n} = 2$

$(\sqrt{n})^2 = 2^2$

$n = 4$

There are 4 scores in the sample.

7 0

3 years ago

A talent manager announced an audition for a female lead role in a web series. Because there are a lot of aspiring talents who a

leonid [27]

The sampling technique used is Simple Random Sampling option fourth would be the best choice.

<h3>What is simple random sampling?</h3>

Simple random sampling is a sampling strategy in which every item in the population has an equal probability of being chosen for the sample.

Simple random sampling selects a sample of objects at random from a population, with each item having an equal chance of being chosen.

Simple random sampling selects items for its sample from a table of random numbers or an electronic random number generator.

Thus, the sampling technique used is Simple Random Sampling option fourth would be the best choice.

Learn more about the simple random sampling here:

brainly.com/question/13219833

#SPJ1

4 0

2 years ago

Southern Oil Company produces two grades of gasoline: regular and premium. The profit contributions are $0.30 per gallon for reg

Contact [7]

Answer:

a) MAX--> PC (R,P) = 0,3R+ 0,5P

b) <u>Optimal solution</u>: 40.000 units of R and 10.000 of PC = $17.000

c) <u>Slack variables</u>: S3=1000, is the unattended demand of P, the others are 0, that means the restrictions are at the limit.

d) <u>Binding Constaints</u>:

1. 0.3 R+0.6 P ≤ 18.000

2. R+P ≤ 50.000

3. P ≤ 20.000

4. R ≥ 0

5. P ≥ 0

Step-by-step explanation:

I will solve it using the graphic method:

First, we have to define the variables:

R : Regular Gasoline

P: Premium Gasoline

We also call:

PC: Profit contributions

A: Grade A crude oil

• R--> PC: $0,3 --> 0,3 A

• P--> PC: $0,5 --> 0,6 A

So the ecuation to maximize is:

MAX--> PC (R,P) = 0,3R+ 0,5P

The restrictions would be:

1. 18.000 A availabe (R=0,3 A ; P 0,6 A)

2. 50.000 capacity

3. Demand of P: No more than 20.000

4. Both P and R 0 or more.

Translated to formulas:

Answer d)

1. 0.3 R+0.6 P ≤ 18.000

2. R+P ≤ 50.000

3. P ≤ 20.000

4. R ≥ 0

5. P ≥ 0

To know the optimal solution it is better to graph all the restrictions, once you have the graphic, the theory says that the solution is on one of the vertices.

So we define the vertices: (you can see on the graphic, or calculate them with the intersection of the ecuations)

V:(R;P)

• V1: (0;0)

• V2: (0; 20.000)

• V3: (20.000;20.000)

• V4: (40.000; 10.000)

• V5:(50.000;0)

We check each one in the profit ecuation:

MAX--> PC (R,P) = 0,3R+ 0,5P

• V1: 0

• V2: 10.000

• V3: 16.000

• V4: 17.000

• V5: 15.000

As we can see, the optimal solution is

V4: 40.000 units of regular and 10.000 of premium.

To have the slack variables you have to check in each restriction how much you have to add (or substract) to get to de exact (=) result.

3 0

3 years ago