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atroni [7]
3 years ago
14

Write an equation for the work necessary to stretch the spring from the relaxed state to distance x1

Mathematics
1 answer:
AveGali [126]3 years ago
3 0
The equation stems from the principle concept of Hooke's Law. After derivation, the general equation for finding the work of a stretch spring is written below:

W = k[(x₂ - x₁) + (x₁ - xn)]
where
k is the spring constant
xn is the natural length of the spring
x₁ is the length after stretching
x₂ is the length after stretching even further

Suppose the spring was only stretched once, then x₁ = x₂. The equation is simplified to:
<em>W = k(x₁ - xn)</em>
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Find the area of the figure<br> A) 114cm<br> B)350cm<br> C)418cm<br> D)447cm
Reika [66]

Answer:

409 is what I got.

Step-by-step explanation:

361 cm, as the square's area

and 48 as the area for the triangle.

Are you sure those are the answer choices because I'm getting 409.

8 0
3 years ago
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PLEASE ANSWER FAST!!!
Ilya [14]
S= 11/12
15%-p=x
35-$18=n
5 0
3 years ago
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Write a numerical expression for the calculation.
Naddik [55]

Answer:

(64-23)8.3

Step-by-step explanation:

Solve the parenthesis first, then multiply

hope this helps! :)

3 0
3 years ago
Allison bought jelly beans to share with her friends. She bought pounds of blueberry jelly beans and pounds of lemon jelly beans
Vaselesa [24]

Answer: 1\dfrac{11}{12}\text{ pounds}

Step-by-step explanation:

The complete question is provided in the attachment.

Given, Amount blueberry jelly beans= 1\dfrac{1}{4} pounds

=\dfrac{5}{4} pounds.

Amount lemon jelly beans = 2\dfrac{1}{3}pounds

=\dfrac{7}{2} pounds

Total jelly beans she bought = Amount blueberry jelly beans + Amount lemon jelly beans

=(\dfrac{5}{4}+\dfrac{7}{3}) pounds

=\frac{15+28}{12}\text{ pounds}\\\\=\dfrac{43}{12}\text{ pounds}

Amount of jelly beans she gave away = 1\dfrac{2}{3}=\dfrac{5}{3}\text{ pounds}

Amount of jelly beans she has left= Total jelly beans - Amount of jelly beans she gave away

=\dfrac{43}{12}-\dfrac{5}{3}\\\\=\dfrac{43-20}{12}\\\\=\dfrac{23}{12}\\\\=1\dfrac{11}{12}\text{ pounds}

She has left 1\dfrac{11}{12}\text{ pounds} of jelly beans.

6 0
3 years ago
Factor Completely.3g^2-78g+75
Umnica [9.8K]

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

                  Hello!

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

❖ 3g^2 - 78g + 75 factored completely is 3(g-1) * (g-25)

First, write the expression as a difference:

3(g^{2} -26g +25)

Then factor the expression:

3(g^{2} - g - 25g + 25)

Factor the expression again:

3 (g*(g-1)-25(g-1))

Your final answer should be:

3(g-1)*(g-25)

~ ʜᴏᴘᴇ ᴛʜɪꜱ ʜᴇʟᴘꜱ! :) ♡

~ ᴄʟᴏᴜᴛᴀɴꜱᴡᴇʀꜱ

3 0
3 years ago
Read 2 more answers
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