Answer:
The percentage of the population carries this trait but displays the dominant phenotype, short eyelashes is the frequency of hetrozygous individuals which is
0.42 or 42 %
Step-by-step explanation:
To solve the question, we note that
p²+2pq+q²=1 and p + q =1
where
p = frequency of the dominant allele
q= frequency of the recessive allele
p² = frequency of homozygous dominant allele
q² = frequency of homozygous recessive allele
2·p·q = frequency of hetrozygous individuals
The frequency of the homozygous recessive individuals q² is 0.09
Therefore the frequency of q = √(0.09) = 0.3, therefore p = 1 - 0.3 =0.7
The percentage of the population carries this trait but displays the dominant phenotype, short eyelashes is the frequency of hetrozygous individuals or 2×p×q = Ae = 2*0.3*0.7 = 0.42
→ 0.42× 100 = 42 %
