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3 years ago

Solve this 6r+7=13+7r

Mathematics

2 answers:

Arisa [49]3 years ago

6 0

6r + 7 = 13 + 7r
- 6r - 6r
 7 = 13 + r
 - 13 - 13 
 -6 = r

alex41 [277]3 years ago

3 0

Let's move all to one side:

6r+7-13-7r=0

and re-arrange to have similar terms together:
6r-7r +7-13=0

let's add up what we can:

-1r-6=0
we can move the -6 to the other side and multiply both sides by -1 and we get:
r=-6 This is the solution.

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3 years ago

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3 years ago

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Verizon [17]

Answer:

arc FD = 236°

Step-by-step explanation:

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3 years ago

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3 years ago

Read 2 more answers

The center of the inscribed circle of Triangle ABC is point , and the center of the circumscribed circle of Triagnle ABC is poin

quester [9]

Answer:

Part A: The center of The inscribed circle is the point S

Part B: The center of The circumscribed circle is the point P

Step-by-step explanation:

Part A: Find the center of The inscribed circle of ΔABC

The inscribed circle will touch each of the three sides of the triangle in exactly one point,

The center of the inscribed circle is the point of intersection between the angle bisectors of the triangle.

So, According to the previous definition:

A₁A₂ and B₁B₂ are the angle bisectors of ∠A and ∠B

So, the inter section between them is the center of The inscribed circle

So, the center of The inscribed circle is the point S

=====================================================

Part B: Find the center of The circumscribed circle of ΔABC

The circumscribed circle is the circle that passes through all three vertices of the triangle.

The center of the circumscribed circle is the point of intersection between the perpendicular bisectors of the sides.

So, According to the previous definition:

P₁P₂ and Q₁Q₂ are the perpendicular bisectors of AB and BC

So, the inter section between them is the center of The circumscribed circle

So, the center of The circumscribed circle is the point P

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4 years ago