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miss Akunina [59]
3 years ago
7

If x-y = 40 and x+y = 70, then what is the value of x squared -y squared ?

Mathematics
1 answer:
OlgaM077 [116]3 years ago
7 0

Let's see what to do buddy...

____________________________

Reminder:

(a + b)(a - b) =  {a}^{2} -  {b}^{2}

So we need to just Multiply above equations like this :

x + y = 70

x - y = 40

(x + y)(x - y) = 70 \times 40

{x}^{2} -  {y}^{2} = 2800

____________________________

And we're done.

Thanks for watching buddy good luck.

♥️♥️♥️♥️♥️

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What is the equation of a line that passes through the points (-3, 4) and (2,8)?
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Given that the line passes through the two points (-3,4) and (2,8)

We need to determine the equation of the line.

<u>Slope:</u>

The slope of the line can be determined using the formula,

m=\frac{y_2-y_1}{x_2-x_1}

Substituting the points (-3,4) and (2,8) in the above formula, we get;

m=\frac{8-4}{2+3}

m=\frac{4}{5}

Thus, the slope of the line is m=\frac{4}{5}

<u>Equation of the line:</u>

The equation of the line can be determined using the formula,

y-y_1=m(x-x_1)

Substituting the point (-3,4) and m=\frac{4}{5} in the above formula, we have;

y-4=\frac{4}{5}(x+3)

y-4=\frac{4}{5}x+\frac{12}{5}

     y=\frac{4}{5}x+\frac{12}{5}+4

     y=\frac{4}{5}x+\frac{32}{5}

Thus, the equation of the line is y=\frac{4}{5}x+\frac{32}{5}

6 0
3 years ago
A store is having a 20% off sale. If the reduced
FinnZ [79.3K]

Answer:

The original price of the item was $83

Step-by-step explanation:

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Select all that justify the following statement.<br><br> 2 • = 1
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Try using negative numbers

6 0
3 years ago
together,sarah's two cats have the same mass as her dog,11 kg.the mass of one cat is 1500 g greater than the mass of the other.
Alika [10]
Let (a) be the first cat
let (b) be the second cat
a +b=11kg-----(1)
a=b+1500g⇒(1.5 kg)-------(2)
so now u have a system of two unknowns
a=11-b
substitute a in (2)
11-b=b+1.5
11-1.5=2b
2b=9.5
b=9.5/2=4.75
subs. b in (1)
a+b=11
a+4.75=11
a=11-4.75=6.25
so cat (a) is 6.25 kg
and (b) is 4.75 kg
hope I helped



6 0
3 years ago
How do you solve a slope for a parallel/perpendicular line?
Burka [1]
The slope of a perpendicular line is the opposite of the reciprocal (negative to positive or positive to negative and then flip the fraction) and the parallel lines have the same slope
4 0
3 years ago
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