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miss Akunina [59]
4 years ago
7

If x-y = 40 and x+y = 70, then what is the value of x squared -y squared ?

Mathematics
1 answer:
OlgaM077 [116]4 years ago
7 0

Let's see what to do buddy...

____________________________

Reminder:

(a + b)(a - b) =  {a}^{2} -  {b}^{2}

So we need to just Multiply above equations like this :

x + y = 70

x - y = 40

(x + y)(x - y) = 70 \times 40

{x}^{2} -  {y}^{2} = 2800

____________________________

And we're done.

Thanks for watching buddy good luck.

♥️♥️♥️♥️♥️

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John purchased a sport utility vehicle for $40,000.00. Sales tax was 6%. The total price, including sales tax, was ________.
pochemuha
The total price would be 42,400
8 0
4 years ago
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Determine the slope for the line that meets each condition stated. Show your work. Passes through the points ( 3 , 5 ) and ( − 1
Kamila [148]

<u><em>Answer:</em></u>

The slope of the line that passes through (-1, -7) and (3, 5) is 3

<u><em>Explanation:</em></u>

<u>The slope of the line is calculated using the following rule:</u>

Slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

<u>We are given the following points:</u>

(3 , 5) representing (x₁ , y₁)

(-1 , -7) representing (x₂ , y₂)

To get the slope, we will simply substitute with the givens in the above equation

<u>This is done as follows:</u>

Slope = \frac{-7-5}{-1-3}=3

You haven't attached the table for the second part. However, follow the same procedure. Pick two points from the table, substitute with them in the above equation and you'll get the slope

Hope this helps :)

4 0
3 years ago
Has x-intercept of 5 and slope of -2/3
sveta [45]
Crosses x axis at (5,0) and slope -⅔. plug in to point slope formula to get
y=-⅔x-10/3
4 0
3 years ago
If 2x squared minus 12x minus 50 equals 0 what is the product of the two values of x
postnew [5]

Answer:

X=3+√34

X=3-√34

7 0
4 years ago
Two forces with magnitudes of 150 and 100 pounds act on an object at angles of 30° and 120°, respectively. Find the direction an
lyudmila [28]
<h2>Answer:</h2>

Magnitude=180.27 \ lbf \\ \\ Direction=63.69 \ degrees

<h2>Step-by-step explanation:</h2>

We have two forces as follows:

<u>First force:</u>

Magnitude: 150 pounds

Angle: 30°


<u>First force:</u>

Magnitude: 100 pounds

Angle: 120°


So the components can be found as follows:

F_{1x}=150cos(30)=129.90 \ lbf\\F_{1y}=150sin(30) = 75 \ lbf \\ \\ F_{2x}=100cos(120)=-50 \ lbf\\F_{2y}=100sin(120) = 86.60 \ lbf


So the components of the resultant force can be found by adding each component of the individual forces as follows:

R_{x}=\Sigma F_{x} \\ R_{y}=\Sigma F_{y} \\ \\ R_{x}=129.90-50=79.90 \ lbf \\ R_{y}=75+86.60=161.6 \ lbf


Finally, the magnitude and direction of the resultant force is:

Magnitude \rightarrow R=\sqrt{R_{x}^2+R_{y}^2}=\sqrt{79.90^2+161.6^2}=180.27 \ lbf \\ \\ Direction \rightarrow \theta=tan^{-1}(\frac{R_{y}}{R_{x}})=tan^{-1}(\frac{161.6}{79.90})=63.69 \ degrees

6 0
3 years ago
Read 2 more answers
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