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3 years ago

Can someone please help me to understand this?

Mathematics

1 answer:

Fittoniya [83]3 years ago

6 0

The average rate of change in y with respect to x over the interval is 7; that is, for every single unit by which x changes, y on average changes by 7 units

hope this answers your question

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Solve on the interval [0,2pi)<br>1+ sin 0=1/2

navik [9.2K]

Try using this app called Calculator Soup, but even tho the name isn’t quite common that doesn’t matter

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3 years ago

Can somebody help plzzzz anyone??? Plzzz

mr Goodwill [35]

Answer: A. 0.0022

Step-by-step explanation:

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3 years ago

One spring, the temperature rose from -5 degrees Celsius to 12 degrees Celsius in 24 hours. How much did the temperature rise in

Furkat [3]

Answer:

17 Degrees Celsius

Step-by-step explanation:

If you like to <em>visualize </em>then recommend using a number line.

Or you can calculate it:

(Difference Temp) = (End Temp) - (Start Temp)

(Difference Temp) = (12) - (-5)

(Difference Temp) = 17

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3 years ago

Find an explicit rule for the nth term of the sequence.The second and fifth terms of a geometric sequence are 18 and 144, respec

vova2212 [387]

Given:

second term = 18

fifth term = 144

The nth term of a geometric sequence is:

$\begin{gathered} a_n\text{ = ar}^{n-1} \\ Where\text{ a is the first term} \\ r\text{ is the common ratio} \end{gathered}$

Hence, we have:

$\begin{gathered} \text{ar}^{2-1}\text{ = 18} \\ ar\text{ = 18} \\ \\ ar^{5-1}=\text{ 144} \\ ar^4\text{ =144} \end{gathered}$

Divide the expression for the fifth term by the expression for the second term:

$\begin{gathered} \frac{ar^4}{ar}\text{ = }\frac{144}{18} \\ r^3\text{ = }\frac{144}{18} \\ r\text{ = 2} \end{gathered}$

Substituting the value of r into any of the expression:

$\begin{gathered} ar\text{ = 18} \\ a\text{ }\times\text{ 2 = 18} \\ Divide\text{ both sides by 2} \\ \frac{2a}{2}\text{ =}\frac{18}{2} \\ a\text{ = 9} \end{gathered}$

Hence, the explicit rule for the sequence is:

$a_n\text{ = 9\lparen2\rparen}^{n-1}$

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2 years ago

The ratio of boys to girls in Mr. Johnson's after-school club is the same as the ratio of boys to girls in Ms. Greene's after-sc

nikdorinn [45]

Answer:

Step-by-step explanation:

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3 years ago

Read 2 more answers