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3 years ago

How do you solve 3 q+2(q+1)

Mathematics

2 answers:

Liula [17]3 years ago

6 0

3q + 2 (q + 1) :Distribute

3q + 2q + 1 :Combine like terms

<em><u>5q + 1</u></em>

vova2212 [387]3 years ago

5 0

$3q+2(q+1)=\ \ \ \ | omiting\ the\ bracket\\\\
3q+2q+2=5q+2\\\\
Solution\ is\ 5q+2.$

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The domain of the graph is -∝ < x < ∝ and the range of the graph is y > -2. Also, the symmetry is x = -3

<h3>The domain and range of the graph</h3>

From the graph, we can see that the x values extend indefinitely

So, the domain of the graph is -∝ < x < ∝

However, the minimum y value is -2 and it increases from there

So, the range of the graph is y > -2

<h3>The intercepts</h3>

This is where the graph crosses the axes

So, we have the intercepts to be

x-intercept = -1 and -5
y-intercept = 1

<h3>Relative max and relative mins points and values, </h3>

The graph has no relative maximum and the relative minimum is (-3, 2)

<h3>Intervals of increase and decrease</h3>

There are the intervals where the function increases and decreases

So, we have the intervals to be

Increasing interval: (-3, ∝)
Decreasing interval: (-∝, -3)

<h3>Intervals of positive and negative</h3>

There are the intervals where the function is positive and negative

So, we have the intervals to be

Positive interval: (-∝, -5) and (1, ∝)
Negative interval: (-5, -1)

<h3>The symmetry</h3>

This is the line that divides the graph equal part

In this case, the symmetry is x = -3

<h3>The end behavior</h3>

Using the intervals where the function is positive and negative, the end behavior is

As x ⇒ ∝, f(x) ⇒ +∝
As x ⇒ -∝, f(x) ⇒ -∝