How do you solve 3 q+2(q+1)
2 answers:
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Z = a + bi
z = 4 + 4i
r² = a² + b²
r² = (4)² + (4)²
r² = 16 + 16
r² = 32
r = 4√(2)
r = 4(1.414)
r = 5.656
z = a + bi
z = rcosθ + (rsinθ)i
z = r(cosθ + i sinθ)
z = 4 + 4i
z = 5.656cosθ + (5.656sinθ)i
z = 5.656(cosθ + i sinθ)
z = 5.656(cos45 + i sin45)
The polar form of 4 + 4i is approximately equal to 5.656(cos45 + i sin45).
z = 4 + 4i
r² = a² + b²
r² = (4)² + (4)²
r² = 16 + 16
r² = 32
r = 4√(2)
r = 4(1.414)
r = 5.656
z = a + bi
z = rcosθ + (rsinθ)i
z = r(cosθ + i sinθ)
z = 4 + 4i
z = 5.656cosθ + (5.656sinθ)i
z = 5.656(cosθ + i sinθ)
z = 5.656(cos45 + i sin45)
The polar form of 4 + 4i is approximately equal to 5.656(cos45 + i sin45).
Answer:
Rectangle
Step-by-step explanation:
Given the points :
(0, 8), (5,2), (0, 2), and (5, 8).
Based on the vertices given :
If we mark the points on a graph and then join the points, we'll Obtain a rectangle ; this is because the length and with are not equal, with a length of 6 unit and width of 5 unit
Attached below is a rough sketch if the plot created in a notebook.
