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Hatshy [7]
3 years ago
6

A biased coin has probability 0.6 of turning up heads. You win $x if a head comes up and you lose $y if a tail comes up. If your

expected winnings is $0, what is the relationship between x and y?
Mathematics
1 answer:
Alexxandr [17]3 years ago
3 0

Answer:

x,y will be in the ratio 2:3

Step-by-step explanation:

Given that a biased coin  has probability 0.6 of turning up heads

In other words, number of heads we obtain by tossing the coin would be binomial with p = 0.6 and q =1-p =0.4

If you toss one time, the distribution of U, no of heads would be

U    0     1

p   0.4   0.6

Winning amount would be 0.6x and losing amount would be 0.4y

If these two are equal then we have

0.6x=0.4y\\Or x:y = 2:3

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90 inches squared

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I'm so confused. This question seems contradicting, and need an explanation.
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1/2 or 0.5 dollars per kg of apples

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6 0
2 years ago
Write the first five digits of 1/7 in base 9 expression
kaheart [24]

Compare 1/7 to consecutive multiples of 1/9. This is easily done by converting the fractions to a common denominator of LCM(7, 9) = 63:

1/9 = 7/63

2/9 = 14/63

while

1/7 = 9/63

Then 1/7 falls between 1/9 and 2/9, so 1/7 = 1/9 plus some remainder. In particular,

1/7 = 1/9¹ + 2/63.

We do the same sort of comparison with the remainder 2/63 and multiples of 1/9² = 1/81. We have LCM(63, 9²) = 567, and

1/9² = 7/567

2/9² = 14/567

3/9² = 21/567

while

2/63 = 18/567

Then

2/63 = 2/9² + 4/567

so

1/7 = 1/9¹ + 2/9² + 4/567

Compare 4/567 with multiples of 1/9³ = 1/729. LCM(567, 9³) = 5103, and

1/9³ = 7/5103

2/9³ = 14/5103

3/9³ = 21/5103

4/9³ = 28/5103

5/9³ = 35/5103

6/9³ = 42/5103

while

4/567 = 36/5103

so that

4/567 = 5/9³ + 1/5103

and so

1/7 = 1/9¹ + 2/9² + 5/9³ + 1/5103

Next, LCM(5103, 9⁴) = 45927, and

1/9⁴ = 7/45927

2/9⁴ = 14/45927

while

1/5103 = 9/45927

Then

1/5103 = 1/9⁴ + 2/45927

so

1/7 = 1/9¹ + 2/9² + 5/9³ + 1/9⁴ + 2/45927

One last time: LCM(45927, 9⁵) = 413343, and

1/9⁵ = 7/413343

2/9⁵ = 14/413343

3/9⁵ = 21/413343

while

2/45927 = 18/413343

Then

2/45927 = 2/9⁵ + remainder

so

1/7 = 1/9¹ + 2/9² + 5/9³ + 1/9⁴ + 2/9⁵ + remainder

Then the base 9 expansion of 1/7 is

0.12512..._9

8 0
2 years ago
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