Question

Solve the question 2w^2-8w-1=(w-2)^2

Answer 1

Answer:

w= 7/4 +1/4 √89 OR w= 7/4 -1/4 √89

Step-by-step explanation:

2w^2-8w-1= (w-2)^2

Multiply (w-2)^2 by (-1)

2w^2-8w-1= -w+2^2

Add w to both sides

2w^2-7w-1= 4

Add 1 to both sides therefore that -1 cancels

2w^2-7w=5

Get the equation equal to 0 by subtracting 5 from both sides

2w^2-7w-5=0

Use the quadratic formula to solve

x= -(-7) plus or minus √(-7)-4(2)(-5)/2(2)

7 plus or minus √89/4