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Bingel [31]
3 years ago
11

1) Billy walks 15 miles every day to soccer practice, and catches a ride home from his grandma. Billy had 5 practices last week.

How many yards did billy walk last week to practice. 1760 yards
2) Marks age is,t, is 3 times his age 10 years ago. Write an equation to represent the statement
Mathematics
1 answer:
nignag [31]3 years ago
3 0

1 )  Billy walks 15 miles every day to soccer practice and he had 5 practices last week.

We know that,  1 mile = 1760 yards

So, 15 miles = (15× 1760) yards = 26400 yards

Thus the total distance walked in 5 practices will be: (26400*5)yards = 132000 yards


2) Mark's current age is t years

So, his age was in 10 years ago =(t-10)years

Given that, his current age is 3 times his age 10 years ago.

So, the equation to represent this situation will be :  t= 3(t-10)


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abruzzese [7]

Answer:

9 quarters and 7 dimes

Step-by-step explanation:

1 quarter = $0.25

1 dime = $0.10

9 (0.25) = $2.25

7 (0.10) = $0.70

2.25 + 0.70 = $2.95

4 0
3 years ago
Find the two-digit number which is 2 times the sum of its digits. Find a statement and number, please.
poizon [28]
A two-digit number is twice the sum of its digit. If the tens digit is 7 less than the unit digit, find the number. 
Let x= the unit digit
Then y= the tens digit
<span>And 10y+x= the number 


</span>x+y= the sum of the digits 
<span>Now we are told that 10y+x=2(x+y) ------1st equation </span>
<span>We are also told that y=x-7 ----------- 2nd Equation </span>
<span>So our equations to solve are: </span>
(1) 10y+x=2(x+y)
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</span>

Hope it helps
5 0
3 years ago
Read 2 more answers
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kherson [118]

Answer:

$25.57

Step-by-step explanation:

First, you have to multiply $5.29 by 2 because she wants to spend $5.29 on 2 pairs of socks.

5.29 * 2 = $10.58

Then you want to add $10.58 and $14.99 together.

$10.58 + $14.99 = $25.57

3 0
3 years ago
19) A submarine ascended from 56.8 meters under the sea level to 27.4 meters under the sea level.
ElenaW [278]

Answer:

29.4 meters

Step-by-step explanation:

Given the following :

A submarine ascended from 56.8 meters under the sea level to 27.4 meters under the sea level.

distance it moved between two positions. Use the "distance on the number line "formula

Initial Position or distance of submarine before ascension = 56.8 meters

Final position after ascension = 27.4 meters

The distance moved by the submarine between the two positions can be obtained by.

(Initial distance - Final distance)

(56.8 - 27.4) = 29.4 meters

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3 years ago
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Vanyuwa [196]

Answer:

a + 20 = 7*12 (multiplied both sides by 12)

a + 20 = 84 (calculated 7*12)

a = 84 - 20 (subtracted 20 on both sides)

a = 64 (calculated 84-20)

4 0
2 years ago
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