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antiseptic1488 [7]
3 years ago
14

1/2x-5>-7 how do I solve this linear inequality

Mathematics
1 answer:
Tems11 [23]3 years ago
8 0

1/2x-5>-7\\1/2*x-5>-7\\1/2*x>-7+5\\1/2*x>-2\\x>-2/(1/2)\\x>-2*2\\x>-4

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13 POINTS- please help me
allsm [11]

Answer:

See explanation

Step-by-step explanation:

16. Two parallel lines are cut by transversal. Angles with measures (6x+20)^{\circ} and (x+100)^{\circ} are alternate exterior angles. By alternate exterior angles, the measures of alternate exterior angles are the same:

6x+20=x+100\\ \\6x-x=100-20\\ \\5x=80\\ \\x=16

Then

(6x+20)^{\circ}=(6\cdot 16+20)^{\circ}=116^{\circ}\\ \\(x+100)^{\circ}=(16+100)^{\circ}=116^{\circ}

17. Two parallel lines are cut by transversal. Angles with measures (2x+12)^{\circ} and (3x-22)^{\circ} are alternate interior angles. By alternate interior angles, the measures of alternate interior angles are the same:

2x+12=3x-22\\ \\2x-3x=-22-12\\ \\-x=-34\\ \\x=34

Then

(2x+12)^{\circ}=(2\cdot 34+12)^{\circ}=80^{\circ}\\ \\(3x-22)^{\circ}=(3\cdot 34-22)^{\circ}=80^{\circ}

18. Two parallel lines are cut by transversal. Angles with measures (6x-7)^{\circ} and (5x+10)^{\circ} are alternate exterior angles. By alternate interior angles, the measures of alternate exterior angles are the same:

6x-7=5x+10\\ \\6x-5x=10+7\\ \\x=17

Then

(6x-7)^{\circ}=(6\cdot 17-7)^{\circ}=95^{\circ}\\ \\(5x+10)^{\circ}=(5\cdot 17+10)^{\circ}=95^{\circ}

19. The diagram shows two complementary angles with measures 2x^{\circ} and 56^{\circ}. The measures of complementary angles add up to 90^{\circ}, then

2x+56=90\\ \\2x=90-56\\ \\2x=34\\ \\x=17

Hence,

2x^{\circ}=2\cdot 17^{\circ}=34^{\circ}

Check:

34^{\circ}+56^{\circ}=90^{\circ}

20. Angles \angle 1 and \angle 2 are vertical angles. By vertical angles theorem, vertical angles are congruent, so

m\angle 1=m\angle 2\\ \\5x+7=3x+15\\ \\5x-3x=15-7\\ \\2x=8\\ \\x=4

Hence,

m\angle 1=(5x+7)^{\circ}=(5\cdot 4+7)^{\circ}=27^{\circ}\\ \\m\angle 2=(3x+15)^{\circ}=(3\cdot 4+15)^{\circ}=27^{\circ}

21. \angle 5 and \angle 8 are supplementary. The measures of supplementary angles add up to 180^{\circ}, so

m\angle 5+m\angle 8=180^{\circ}\\ \\3x-40+7x-120=180\\ \\10x-160=180\\ \\10x=180+160\\ \\10x=340\\ \\x=34

Therefore,

m\angle 5=(3x-40)^{\circ}=(3\cdot 34-40)^{\circ}=62^{\circ}\\ \\m\angle 8=(7x-120)^{\circ}=(7\cdot 34-120)^{\circ}=118^{\circ}\\ \\62^{\circ}+118^{\circ}=180^{\circ}

7 0
3 years ago
What is the value of v in the equation 3(2v + 1)=-15(5v + 16)​
Darina [25.2K]

Answer:

v = -3

Step-by-step explanation:

6v+3= -75v - 15 (16)

81v=  -243

then put it over -3 then

-243 over 81

7 0
3 years ago
Read 2 more answers
Triangle A B C is cut by line segment S T. Line segment S T goes from side A B to side C B. Lines S T and A C are parallel. The
maksim [4K]

Answer:

Option C.

Step-by-step explanation:

Given information: In triangle ABC, ST║AC, SB=10 ft, BT=9 ft and CT=2.7 ft.

Triangle proportionality theorem: If a line segment parallel to a side of a triangle then the line segments divides the remaining sides proportionally.

Using triangle proportionality theorem we get

\dfrac{SA}{SB}=\dfrac{CT}{BT}

\dfrac{SA}{10}=\dfrac{2.7}{9}

On cross multiplication we get

9\times SA=2.7\times 10

9SA=27

Divide both sides by 9.

SA=3

The length of SA is 3ft.

Therefore, the correct option is C.

8 0
3 years ago
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What fracction is closets to -3/5, 2/5 0r 4/5
Andreas93 [3]

Answer:

2/5

Step-by-step explanation:

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3 years ago
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Does anyone know how to solve this problem?
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He needs $78.95 to buy 5 of each
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