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Liula [17]
3 years ago
10

At the beach, 29% of people are on the boardwalk and 26% are on the sand. If the rest are in the water, what percentage of peopl

e are in the water?
help asappp
Mathematics
1 answer:
natali 33 [55]3 years ago
6 0

Answer:

45% of the people are in the water

Step-by-step explanation:

100%-29%=71%

71%-26%=45%

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A bag contains seven tiles labeled B, C, D, E, F, G, and H. One tile will be randomly picked. What is the probability of picking
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\sf \dfrac{1}{7}

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3 years ago
A bag contain 3 black balls and 2 white balls.
Troyanec [42]

Answer:

Step-by-step explanation:

Total number of balls = 3 + 2 = 5

1)

a)

Probability \ of \ taking \ 2 \ black \ ball \ with \ replacement\\\\ = \frac{3C_1}{5C_1} \times \frac{3C_1}{5C_1} =\frac{3}{5} \times \frac{3}{5} = \frac{9}{25}\\\\

b)

Probability \ of \ one \ black \ and \ one\ white \ with \ replacement \\\\= \frac{3C_1}{5C_1} \times \frac{2C_1}{5C_1} = \frac{3}{5} \times \frac{2}{5} = \frac{6}{25}

c)

Probability of at least one black( means BB or BW or WB)

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d)

Probability of at most one black ( means WW or WB or BW)

=\frac{2}{5} \times \frac{2}{5} + \frac{3}{5} \times \frac{2}{5} \times \frac{2}{5} + \frac{3}{5}\\\\= \frac{4}{25} + \frac{6}{25} + \frac{6}{25}\\\\=\frac{16}{25}

2)

a) Probability both black without replacement

  =\frac{3}{5} \times \frac{2}{4}\\\\=\frac{6}{20}\\\\=\frac{3}{10}

b) Probability  of one black and one white

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c) Probability of at least one black ( BB or BW or WB)

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d) Probability of at most one black ( BW or WW or WB)

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43 i alredy learned that in school

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