Answer: They are parallel
Step-by-step explanation:
If two lines are parallel , then they must have the same slope and if two lines are perpendicular , the product of their slope must be -1.
To check this , we must calculate the slope of the two lines given.
Slope = 
from the first point
= 2
= 1
= 5
= -1
substituting the values
slope 1 = 1 - 2 / -3 - 5
slope1 = -1 / -8
slope 1 = 1/8
Using the same format to calculate the slope of the second line
= -2
= 0
= -1
= 15
slope 2 = 0 - (-2) / 15 - (-1)
slope 2 = 2/16
slope 2 = 1/8
Since slope 1 = slope 2 , this implies that the lines are parallel
Hello!
If you want to find an equation that is parallel to another equation, and passing through the point (1, 4), you need to create a new equation with the same slope, you need to substitute the given point into the new equation to find the y-intercept.
m = 3, y = 3x + b (substitute the ordered pair)
4 = 3(1) + b (simplify)
4 = 3 + b (subtract 3 from both sides)
b = 1
Therefore, the line parallel to the line y = 3x - 2 and passing through the point (1, 4) is y = 3x + 1.
Answer:
Step-by-step explanation:
FIRST ONE D
SECOUND ONE IS 52
THRID 505
FORD 40
FIVE 18
Answer:

Step-by-step explanation:
![(\sqrt{3} +4)(1+\sqrt{3})\\\\= \sqrt{3}(1+\sqrt{3} )+4(1+\sqrt{3})\\\\= \sqrt{3} + (\sqrt{3} )^2 + 4 + 4\sqrt{3} \\\\= \sqrt{3} + 3+4+4\sqrt{3} \\\\= 7 + \sqrt{3} + 4\sqrt{3} \\\\Take \ \sqrt{3} \ common\\\\= 7 + \sqrt{3} (1+4)\\\\= 7 + \sqrt{3}(5)\\\\= 7 + 5\sqrt{3} \\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%28%5Csqrt%7B3%7D%20%2B4%29%281%2B%5Csqrt%7B3%7D%29%5C%5C%5C%5C%3D%20%5Csqrt%7B3%7D%281%2B%5Csqrt%7B3%7D%20%29%2B4%281%2B%5Csqrt%7B3%7D%29%5C%5C%5C%5C%3D%20%5Csqrt%7B3%7D%20%2B%20%28%5Csqrt%7B3%7D%20%29%5E2%20%2B%204%20%2B%204%5Csqrt%7B3%7D%20%5C%5C%5C%5C%3D%20%5Csqrt%7B3%7D%20%2B%203%2B4%2B4%5Csqrt%7B3%7D%20%20%5C%5C%5C%5C%3D%207%20%2B%20%5Csqrt%7B3%7D%20%20%2B%204%5Csqrt%7B3%7D%20%5C%5C%5C%5CTake%20%5C%20%5Csqrt%7B3%7D%20%5C%20common%5C%5C%5C%5C%3D%207%20%2B%20%5Csqrt%7B3%7D%20%281%2B4%29%5C%5C%5C%5C%3D%207%20%2B%20%5Csqrt%7B3%7D%285%29%5C%5C%5C%5C%3D%207%20%2B%205%5Csqrt%7B3%7D%20%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>