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Mars2501 [29]
2 years ago
11

A student solved this problem by working backwards.

Mathematics
1 answer:
inna [77]2 years ago
3 0
6
I hope this helped !!
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Find the domain and range of each relation. Then determine if the relation is a function. ​
Vlad [161]

Answer:

There is no fixed domain, meaning it is ongoing

The range is from -1 ≤ x ≤ 3

It is a function

Step-by-step explanation:

Domain refers to the x values. If there was a domain then there would be a dot or a point signalling that there is a fixed domain, however, there are arrows meaning that it will keep going.

The range refers to the y-values. The lowest y-value is -1 and the highest is 3.

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3 0
3 years ago
How to find all real solutions
AlladinOne [14]
\bf \sqrt{\sqrt{x-5}+x}=5\leftarrow \textit{squaring both sides}
\\\\
\sqrt{x-5}+x=25\implies \sqrt{x-5}=25-x\leftarrow \textit{squaring both sides}
\\\\
x-5=(25-x)^2\implies x-5=625-50x+x^2
\\\\
0=x^2-51x+630\implies 0=(x-30)(x-21)

and surely you'd know what the roots are

7 0
3 years ago
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