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3 years ago

Please help me anyone...

Mathematics

1 answer:

zavuch27 [327]3 years ago

5 0

Answer: what grade are you in im in 7th

Step-by-step explanation:

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Given a normal distribution with mu equals 100μ=100 and sigma equals 10 commaσ=10, complete parts (a) through (d). loading...

m_a_m_a [10]

I believe the parts are:

A. What is the probability that Upper X greater than 95X>95?

B. What is the probability that Upper X less than 75X<75?

C.What is the probability that Upper X less than 85X<85 and Upper X greater than 125X>125?

D. 95% of the values are between what two X-values (symmetrically distributed around the mean)?

<u>Solution:</u>

We use the equation for z score:

z = (X – μ) / σ

Then use the standard normal probability tables to locate for the value of P at indicated z score value.

A. Z = (95 – 100) / 10 = - 0.5

Using the tables, the probability at z = -0.5 using right tailed test is:

P = 0.6915

B. Z = (75 – 100) / 10 = - 2.5

Using the tables, the probability at z = -2.5 using left tailed test is:

P = 0.0062

C. Z = (85 – 100) / 10 = - 1.5

Using the tables, the probability at z = -2.5 using left tailed test is:

P = 0.0668

Z = (125 – 100) / 10 = 2.5

Using the tables, the probability at z = 2.5 using right tailed test is:

P = 0.0062

So the probability that 85<X and X>125 is:

P(total) = 0.0668 + 0.0062

P(total) = 0.073

D. P(left) = 0.025, Z = -1.96

P(right) = 0.975, Z = 1.96

The X’s are calculated using the formula:

X = σz + μ

At Z = -1.96

X = 10 (-1.96) + 100 = 80.4

At Z = 1.96

X = 10 (1.96) + 100 = 119.6

<span>So 95% of the values are between 80.4 and 119.6 (80.4< X <119.6).</span>

7 0

4 years ago

Use the figure shown. Let point D be at (-4,1) . Use the sides of triangle BDA to find the slope of the line.

gavmur [86]

The slope of the line shown in the figure having equation x + 2y = 0 is 1/2.

The point A is at ( -2 , 1 ), point B is at ( -4 , 2 ) and Point C is at ( -2 , 2 ).

Let point D be at ( -4 , 1 ).

Now the new triangle is ΔBDA and the corner points are A is at ( -2 , 1 ), point B is at ( -4 , 2 ) and point D is at ( -4 , 1 ).

The equation of line passing through two points is given by:

$(y-y_{1} ) = (\frac{y_{2}-y_{1} }{x_{2} - x_{1} })(x - x_{1} )$

The equation of line passing through two points A( -2 , 1 ) and B( -4 , 2 ) IS

y - 1 = ((2-1)/(-4-(-2))) (x-(-2))

y - 1 = (1/(-2)) (x+2)

2y -2 = -x -2

x + 2y = 0

The equation of straight line is x + 2y = 0

The equation in slope intercept form can be written as,

y = x/2 + 0

Slope = m = 1/2

Intercept = c = 0

So, we can conclude that 1/2 is the slope of the line .

To know more about Slope - intercept form refer to link:

brainly.com/question/1884491

#SPJ1

3 0

2 years ago

What is an equation in point-slope form of the line that passes through (−1,−4) and (2, 5)?

lakkis [162]

Answer:

I think y−4=3(x−1)

5 0

2 years ago

Read 2 more answers

Find the unknown side length for the parallelogram.

snow_tiger [21]

I hope this helps you

Area=base.height

98=base.9

base=98/9

base=10,8

3 0

3 years ago

Two sides of a triangle are 7 and 11 the length of the third side x is expressed

slava [35]

Answer:

The sum of the lengths of any two sides of a triangle must be greater than the length of the third side. ... No; The sum of the lengths of any two sides of a triangle must be greater than the length of the third side. ANSWER: No; 9.

8 0

3 years ago