The required solution is ∠RQT = 202° and ∠QTS = 51°
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<h3>What is a cyclic quadrilateral?</h3>
A cyclic quadrilateral is a quadrilateral which has all its four vertices lying on a circle. It is also called as inscribed quadrilateral.
Its main property is that the sum of opposite angles of inscribed quadrilateral is always 180 degrees.
Now, the given circle has a cyclic quadrilateral QRST in which it is given that ∠RQT = 202° and ∠QRS = 129°
Since,sum of the opposite angles of a cyclic quadrilateral = 180°
⇒∠QTS + ∠QRS = 180°
⇒ ∠QTS + ∠129° = 180°
⇒ ∠QTS = 180° - ∠129°
⇒ ∠QTS = 51°
Hence,the requires angles are ∠RQT = 202° and ∠QTS = 51°.
More about cyclic quadrilateral :
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Answer:
Imaginary
Step-by-step explanation:
C) They satisfy equation A but not equation B
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EXPLANATION
4y - 3x = 16
4(0.25) - 3(-5) = 16
1 -3(-5) = 16
1 + 15 = 16
16 = 16
-x - 8y = 3
-5 - 8(0.25) = 3
-5 - 2 = 3
-7 = 3
Doesnt solve equation B
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Answer:
Step-by-step explanation:
