Answer:
awser 29
Step-by-step explanation:
`22
Answer:
Not possible.
Step-by-step explanation:
Addition of Matrix A and Matrix B is possible only if the order of matrix A is same as the order of matrix B.
Order of a matrix with 
rows and 
columns is 
.
Here, matrix A is ![\left[\begin{array}{ccc}2&-4\\-4&10\\0&-8\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%26-4%5C%5C-4%2610%5C%5C0%26-8%5Cend%7Barray%7D%5Cright%5D)
Matrix B is ![\left[\begin{array}{ccc}0&-4&6\\2&-10&4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%26-4%266%5C%5C2%26-10%264%5Cend%7Barray%7D%5Cright%5D)
.
Multiplying a matrix by a constant doesn't change its order.
So, order of matrix A is 
as it has 3 rows and 2 columns.
The order of matrix 3B is 
as it has 2 rows and 3 columns.
Therefore, addition is not possible as the order is different.
So we can set x= width
2x+2 = length
so 2(x)+2(2x+2)= 76
so that will give us 2x+4x+4=76
6x=72
x=12
so 12 is width and 26 is length
S and P are mutually exclusive events.
P ( S ) = 20% = 0.20
P ( T ) = 22 % = 0.22
The probability of mutually exclusive events:
P ( S or T ) = P ( S ) + P ( T )
P ( S or T ) = 0.20 +0.22 = 0.42
Answer: The probability of ( S or T ) is 0.42 or 42 %.
Answer:
3
Step-by-step explanation:
C(n) = 5n, 0 ≤ n ≤ 10 You would use this equation for finding the cost of 10 shirts. Since 10 is equal to 10.
C(n) = 5n, 0 ≤ n ≤ 10 ← You can ignore the 0 ≤n ≤10 part.
C(10) = 5(10) Input the value 10 as x.
C(10) = 50 Simplified
Next,
C(n) = 4n + 5, n > 10 You would use this equation for finding the cost of 12shirts. Since 12 is greater than 10.
C(n) = 4n + 5, n > 10 ← You can ignore the n>10 part.
C(12) = 4(12) + 5, n > 10 Input the value of 12 as x.
C(12) = 48 + 5 Simplify
C(12) = 53
Finally,
The question is asking you to find the difference between the cost of 12 shirts and the cost of 10 shirts. So the formula would be C(12) - C(10).
C(12) - C(10)
(53) - (50) Input the values of C(12) and C(10).
= 3 Simplify.
The answer is 3.
