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3 years ago

You buy a game for $ 40 , and the sales tax is $2 . What percent of the game price are you paying in sales tax?

2 answers:

5 0

So you are buying a video game that is worth $40 and you had to use the sales tax, with is an extra $2, so the percentage would be 5% since 5% = $2 and when you finish filling the percentage to 100%, it would be 100% = $40.

Hope this helped!

Nate

Rina8888 [55]3 years ago

3 0

Answer: 5% or .05

Step-by-step explanation:

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DanielleElmas [232]

Start by distributing the 6 through the parenthses on the left side.

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Solving from here, I would subtract 24 from both sides to get 6x = 6.

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Rufina [12.5K]

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3 years ago

Find the slope of a line that passes through (-2,1) and (4,9)

melamori03 [73]

Answer:

m = 4/3

Step-by-step explanation:

To find the slope of a line use the formula, where "m" means slope:

$m=\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

*You don't need to show this part on paper*

Choose which point you want to be point 1 and point 2. Remember the points are written (x, y).

Point 1: (-2, 1) x₁ = -2 y₁ = 1

Point 2: (4, 9) x₂ = 4 y₂ = 9

Substitute the coordinates into the formula:

*Show this part on paper*

$m=\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

$m=\frac{9-1 }{4-(-2) }$ Simplify

$m=\frac{8 }{6 }$ Reduce by dividing by 2

$m=\frac{4 }{3 }$ Slope

The slope of the line is 4/3

8 0

3 years ago

Please answer 7X-20-90

JulijaS [17]

First, you need to collect the like terms; 7x + (-20 - 90). Next simplify; 7x - 110
answer; 7x - 110

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3 years ago

The points A(1, 4), B(5,1) lie on a circle. The line segment AB is a chord. Find the equation of a diameter of the circle.

tangare [24]

Check the picture below.

well, we want only the equation of the diametrical line, now, the diameter can touch the chord at any several angles, as well at a right-angle.

bearing in mind that <u>perpendicular lines have negative reciprocal</u> slopes, hmm let's find firstly the slope of AB, and the negative reciprocal of that will be the slope of the diameter, that is passing through the midpoint of AB.

$\bf A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{5}-\underset{x_1}{1}}}\implies \cfrac{-3}{4} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{slope of AB}}{-\cfrac{3}{4}}\qquad \qquad \qquad \stackrel{\textit{\underline{negative reciprocal} and slope of the diameter}}{\cfrac{4}{3}}$

so, it passes through the midpoint of AB,

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{5+1}{2}~~,~~\cfrac{1+4}{2} \right)\implies \left(3~~,~~\cfrac{5}{2} \right)$

so, we're really looking for the equation of a line whose slope is 4/3 and runs through (3 , 5/2)

$\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{\frac{5}{2}}) \stackrel{slope}{m}\implies \cfrac{4}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{\cfrac{5}{2}}=\stackrel{m}{\cfrac{4}{3}}(x-\stackrel{x_1}{3})\implies y-\cfrac{5}{2}=\cfrac{4}{3}x-4 \\\\\\ y=\cfrac{4}{3}x-4+\cfrac{5}{2}\implies y=\cfrac{4}{3}x-\cfrac{3}{2}$

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3 years ago