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Katarina [22]
3 years ago
10

With water from one hose, a swimming pool can be filled in 9 hours. A second, larger hose used alone can fill the pool in 2 hour

s. How long would it take to fill the pool if both hoses were used simultaneously?
Mathematics
1 answer:
Monica [59]3 years ago
5 0

1/9 + 1/2 = 1/x

Let x = length of time it will take both hoses to work together

Multiply both sides by 18x.

2x + 9x = 18

10x = 18

x = 18/10

x = 9/5

x = 1.8 hours

In other words, if both hoses work together, the pool can be filled in 1 hour and 48 minutes.

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2,522,880,000 segundos.

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lisov135 [29]

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Step-by-step explanation:

\text{The volume of a cylinder is}\\ \\ V=h\pi r^2,\ r=16/2=8,/ h=21\\ \\ V=21\pi (8^2)\\ \\ V=1344\pi

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AlladinOne [14]

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a

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I need help urgent plz someone help me solved this problem! Can someone plz help I’m giving you 10 points! I need help plz help
VMariaS [17]

Answer: a) 8.779 years

               b) 8.664 years

<u>Step-by-step explanation:</u>

a)

A=P\bigg(1+\dfrac{r}{n}\bigg)^{nt}

  • A: accumulated amount (balance)
  • P: principal amount (original/initial investment)
  • r: interest rate (convert to a decimal)
  • n: number of times compounded per year
  • t: number of years

Given: A = 1800, P = 900, r = 8% = 0.08, n = 3, t = unknown

1800=900\bigg(1+\dfrac{0.08}{3}\bigg)^{3t}\\\\\\2=\bigg(1+\dfrac{0.08}{3}\bigg)^{3t}\\\\\\ln\ 2=ln \bigg(1+\dfrac{0.08}{3}\bigg)^{3t}\\\\\\ln\ 2=3t\ ln\bigg(1+\dfrac{0.08}{3}\bigg)\\\\\\\dfrac{ln\ 2}{3\ ln\bigg(1+\dfrac{0.08}{3}\bigg)}=t\\\\\\\large\boxed{8.779=t}

b)  

A=Pe^{rt}

1800=900e^{0.08t}\\\\\\2=e^{0.08t}\\\\\\ln\ 2=0.08t\\\\\\\dfrac{ln\ 2}{0.08}=t\\\\\\\large\boxed{8.664=t}

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A farmer is building a grain silo for storage. he estimates that will need 256 cubic yards of storage. the grain silo will be sh
Vlad1618 [11]
Check the picture below.

keeping in mind that a cube is just a rectangular prism with all equal sides.

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