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Lana71 [14]
4 years ago
10

The area of the base of a rectangular juice box is 4 1/2 sq.in. If the volume of the box is 18 cubic inches, how tall is the box

?
Mathematics
1 answer:
Ksju [112]4 years ago
6 0
Volume = Area x Height. We are given Volume and Area, so plug in and solve for Height (Height = Volume/Area)

18in^3 = 4.5 in^2 x Height (divide both sides by 4.5) -> 4in = Height
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Arisa [49]
-7d > 21
d < -3

Remember the sign flips when you multiply or divide by a negative number.
3 0
3 years ago
What is the volume of the square-based pyramid?
grandymaker [24]

Answer:

Volume of square-based pyramid = 96 in³

Step-by-step explanation:

Given:

Base side of square = 6 inch

Height of pyramid = 8 inch

Find:

Volume of square-based pyramid

Computation:

Area of square base = Side x Side

Area of square base = 6 x 6

Area of square base = 36 in²

Volume of square-based pyramid = (1/3)(A)(h)

Volume of square-based pyramid = (1/3)(36)(8)

Volume of square-based pyramid = (1/3)(36)(8)

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6 0
3 years ago
Help me please help ASAP please I will mark brainliest if I can
Over [174]

Answer:

60-9pi if you need that rounded then 31.73

Step-by-step explanation:

10*6= 60

the two semi circles make one full circle. a circle formula is pi*r^2 = pi*3^2= 9pi

then subtract 9pi from 60

60-9pi = 31.73

8 0
3 years ago
Read 2 more answers
The American Management Association is studying the income of store managers in the retail industry. A random sample of 49 manag
VashaNatasha [74]

Answer:

a) The 95% confidence interval for the income of store managers in the retail industry is ($44,846, $45,994), having a margin of error of $574.

b) The interval mean that we are 95% sure that the true mean income of all store managers in the retail industry is between $44,846 and $45,994.

Step-by-step explanation:

Question a:

We have to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a p-value of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.96\frac{2050}{\sqrt{49}} = 574

The lower end of the interval is the sample mean subtracted by M. So it is 45420 - 574 = $44,846.

The upper end of the interval is the sample mean added to M. So it is 45420 + 574 = $45,994.

The 95% confidence interval for the income of store managers in the retail industry is ($44,846, $45,994), having a margin of error of $574.

Question b:

The interval mean that we are 95% sure that the true mean income of all store managers in the retail industry is between $44,846 and $45,994.

5 0
3 years ago
Plz help me i really need this i will give brainliest​
Leno4ka [110]

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8 0
3 years ago
Read 2 more answers
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