Answer:
Depth of the rain gutter is 8 inches
Step-by-step explanation:
Let’s assume ‘x’ is the depth of the rain gutter
Then the width of the rain gutter can be written as 16 - 2x
Cross sectional area
A = depth x width
Substitute values
A = x*(16 - 2x)
A = 16x – 2x^2
Now according to axis of symmetry for maximum area x = -b/2a
x = -16/2*(-2)
x = 4 inches depth of rain gutter, substitute the value of x to get
Width of rain gutter 16 – 2(4) = 8 inches
Area of the rain gutter for maximum water flow
A = 4 * 8
A = 32 square inch.
Irrational because it can not be written as a fraction
<span>To draw two number lines showing that 0.200 and 1/5 are equivalent, we draw a number line divided into 5 equal segments with range from 0 to 1.0, the points on this line will be at 0.2,0.4,0.6,0.8 and 1.0. Next we draw second number line with range from 0 to 5/5 with 5 equal segments. The points on this line will be 1/5, 2/5,3/5,4/5 and 5/5. The equal segments will show that these values 0.200 and 1/5 are equivalent.</span>
Answer:
Step-by-step explanation:
Answer:
462 cu. in
Step-by-step explanation:
See attached formula
