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VMariaS [17]
3 years ago
12

Which equation represents a line that passes through (4, 1/3) and has a slope of 3/4? ​

Mathematics
1 answer:
Assoli18 [71]3 years ago
3 0

Answer:

y = 3/4x - 8/3

Step-by-step explanation:

If you have any questions about the way I solved it, don't hesitate to ask me in the comments below ;)

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C Jacob

Step-by-step explanation:

Alfredo: 157.5/18 = 8.75

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Jacob: 142.5/15 = 9.53

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7 0
3 years ago
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3 0
3 years ago
Solve 3x^2 + 6x+15=0
Elden [556K]

Answer:

The solution of given equation is ( - 1 + 2 i ) , ( - 1 - 2 i )

Step-by-step explanation:

Given equation as :

3 x² + 6 x +15 = 0

The value of x fro the quadratic equation a x² + b x + c = 0 is obtained as

x = \frac{-b\pm \sqrt{b^{2}-4ac}}{2a}

So , from given eq , the value of x is now obtain as

x = \frac{-b\pm \sqrt{b^{2}-4\times a\times c}}{2\times a}

Or, x =  \frac{-6\pm \sqrt{6^{2}-4\times 3\times 15}}{2\times 3}

Or, x = \frac{\sqrt{-144} }{6}

∴   x = ( - 1 + 2 i ) , ( - 1 - 2 i )

Hence The solution of given equation is ( - 1 + 2 i ) , ( - 1 - 2 i )  Answer

6 0
3 years ago
What is the equation of a line with a slope of -2 that passes through the point (-2,12)?
slavikrds [6]

Answer:

y=-2x + 8 which is the required equation

Which is option C

Step-by-step explanation:

Given:

Slope = m = -2

Given points are ( -2,12)

Which is

x = -2 and y =12

TO find:

Equation of line passing through these points = ?

Solution:

The point slope form of a line is

y = mx + c

Here we don't know the value of c

To find it

Putting y = 12 , x= -2 and y = -2 in the given equation

y = mx + c

Putting values it becomes

12 = (-2)*(-2) + c

12 = 4 + c

Subtracting 4 from both sides

12-4 = 4 -4 + c

8 = c

Now we have

m = -2 and c= 8

So equation of a line is given by

y = mx + c

Putting value of m and c

y = -2*x + 8

y=-2x + 8 which is the required equation


7 0
2 years ago
Read 2 more answers
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