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morpeh [17]
3 years ago
5

Solve. How can I solve this division 12 divided by 144140

Mathematics
2 answers:
Aleksandr [31]3 years ago
8 0
The answer is 0.00008325

Hope this helps!
Lunna [17]3 years ago
4 0
12,011 is the best answer.......!.!.!.!.!.!.!.!.!.!.!.!..!
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3. An automobile manufacturer has three factories, A, B, and C. They produce 50, 30, and 20%,
julsineya [31]

Answer:

Step-by-step explanation:

P(white) = .5%2A.3%2B.3%2A.4%2B.2%2A.25=+.15+%2B+.12+%2B.05+=+.32 0r 32%

4 0
3 years ago
A company manufactures and sells novelty mugs.The manufacturing costs consists of a fixed cost of R8 000 and a variable cost of
Sauron [17]
Ok so

8000=cost
profit-8000
then
another cost is 15rand per mug
but profit of 35 rand
35-15=20
profit of 20rand per mug

profit=R20m-R8000
where m=number of mugs sold
(R20 means 20 rand)


f(m)=R20m-R8000

break even means cost=earned
basically, when profit=0
0=R20m-R8000
add 8000 to both sides
R8000=R20m
divide both sides by 20
400=m

break even is 400 mugs


graph should be easy enough
put a point at (0,-8000) and at (400,0) then connect them



profit
f(x)=R20x-R8000
break even is 400 mugs

put points (0,-8000) and (400,0) and connect them
4 0
3 years ago
Does the mixed number 4 3/4 make each equation true? Choose Yes or No for each equation.
zhuklara [117]

Answer:

first one: yes

second one: yes

third one: no

fourth one: yes

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Please solve this and give answer
Nikolay [14]

Answer:

Step-by-step explanation:

4 0
3 years ago
A small manufacturing firm has 250 employees. Fifty have been employed for less than 5 years and 125 have been with the company
sukhopar [10]

Answer:

Step-by-step explanation:

Given that a small manufacturing firm has 250 employees. Fifty have been employed for less than 5 years and 125 have been with the company for over 10 years. So remaining 75 are between 5 and 10 years.

Suppose that one employee is selected at random from a list of the employees

A) Probability that the selected employee has been with the firm less than 5 years = \frac{50}{250 } \\= 0.20

B) Probability that the selected employee has been with the firm between 5 and 10 years

= \frac{75}{250 } \\= 0.30

C) Probability that the selected employee has been with the firm more than 10 years

= \frac{125}{250} =0.50

a) P(A) = 0.2

P(C) = 0.5

P(A or B) = 0.2+0.3 = 0.5

P(A and C) = 0 (since A and C are disjoint)

7 0
3 years ago
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