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kozerog [31]
3 years ago
6

marcus plots the point (4,7) in quadrant i on the coordinate plane . nicole then plots the points (4,-3) in quadrant Iv of the s

ame graph. explain what the line that goes through those two points would look like and evaluate the slope
Mathematics
2 answers:
Lady_Fox [76]3 years ago
6 0

Answer:

Vertical line at x=4

Slope = Undefined or no slope

Step-by-step explanation:

Let

(x_1,y_1) = (4,7)\\(x_2,y_2)=(4,-3)

We can observe that the x-coordinates of both the points are same which means that the line will be a <u>vertical line parallel to y-axis at x=4.</u>

The run of the graph is zero for a vertical line, which is the denominator in the slope formula so the line will have no slope ..

Lera25 [3.4K]3 years ago
3 0

Answer:

The points have the same x-coordinates.

The line would be vertical.

The line has no slope.

The run = 0, which would create an undefined fraction.

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Answer:

D = -6, E = -8 , F = 0

Step-by-step explanation:

standard form = x^{2} + y^{2} + Dx + Ey + F = 0

now, when circle passes through (3,-1);

⇒ 3^{2} + (-1)^{2} + D(3) + E(-1) + F = 0

⇒ 3D - E + F + 10 = 0    ...............( equation 1)

when circle passes through (-2,4);

⇒ (-2)^{2} + 4^{2} + D(-2) + E(4)+ F = 0

⇒ -2D + 4E + F + 20 = 0    ...............( equation 2)

when circle passes through (6,8);

⇒ 6^{2} + 8^{2} + D(6) + E(8) + F = 0

⇒ 6D + 8E + F + 100= 0       ................( equation 3)

by solving these 3 equations , we get;

D = -6, E = -8, F = 0

hence,

standard form = x^{2} + y^{2} + Dx + Ey + F = 0

                        = x^{2} + y^{2} - 6x - 8y = 0

5 0
3 years ago
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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