2sin²(-2490)+tan 1410=2sin²(-330-6*360)+tan (330+3*360)=
=2sin²(-330)+tan (330)=2 sin²(30-1*360)+tan (-30)=
=2sin²(30)-tan (30)=2(1/2)²-√3/3=1/2-√3/3)=(3-2√3)/6
Answer: 2 sin²(-2490)+tan (1410)=(3-2√3)/6 (≈-0.07735...)
Answer:
10,000
Step-by-step explanation:
yes
Answer:
2
Step-by-step explanation:
The given equation of line is
We need to find the slope of a line which is perpendicular to the given line.
The given equation can be rewritten as
...(i)
If a line is defined as
, then the slope of the line is
In equation (i), a=3, b=6 and c=18. So, slope of the line is
Let
be the slope of perpendicular line.
We know that product of two perpendicular line is -1.
Multiply both sides by -2.
Therefore, the slope of perpendicular line is 2.
Answer:
Option C. 
Step-by-step explanation:
we have
-----> equation A
-----> equation B
Solve the system of equations by graphing
Remember that the solution of the system of equations is the intersection point both graphs
The intersection point is (1,3)
see the attached figure
therefore
The solution of the system of equations is

Find the difference
